Unit 9: Applications of Integration
The definite integral at work: area between curves, solids built by slicing and revolving, motion from velocity, work against a force, exponential growth.
21 topics · 74 questions
Each topic is a path, not a menu: work down it in order and every question builds on the one above. Click any of them to watch the answer draw itself.
6.1 The Area Between Two Curves
- How it worksHow does slicing the region between two curves into thin vertical strips turn the area into a single integral?
- Common mistakeWhy isn't the area between two curves just the integral of the top function minus the integral of the bottom function taken separately?
- Worked exampleFind the area between f(x) = x2 - 4 and g(x) = 4 - x2.
- Worked exampleFind the area between f(x) = x2 and g(x) = x + 2 between their two points of intersection.
Your turn1 of 2
Find the area between f(x) = 7 - x2 and g(x) = x2 - 7.6.1 The Area Between Curves That Cross More Than Once
- How it worksHow do you find every intersection point first so you know where the top and bottom functions trade places?
- Worked exampleFind the total area between f(x) = sin(x) and g(x) = cos(x) from x = 0 to x = π.
- Common mistakeWhy doesn't integrating (top minus bottom) across the whole interval work when the curves cross in the middle?
Your turn1 of 2
Find the total area between f(x) = 6sin(x) and g(x) = 6cos(x) from x = 0 to x = π.6.1 Finding Area by Integrating with Respect to y
- How it worksHow does rewriting each curve as x in terms of y turn a sideways region into an ordinary area integral?
- Going furtherWhat happens to an area calculation when a region can't be described as a single function of x anywhere?
- Worked exampleFind the area enclosed by x = y2 and x = y + 2 by integrating with respect to y.
Your turn1 of 2
Find the area enclosed by x = y2 and x = 4y + 6 by integrating with respect to y.6.2 Volumes by Slicing with General Cross-Sections
- How it worksHow does stacking infinitely many thin cross-sectional slabs turn a solid's volume into a single integral?
- Common mistakeWhy isn't the volume of a solid with cross-sections just the area of one cross-section multiplied by the total length?
- Worked exampleFind the volume of a solid whose base is bounded by y = x2 and y = 4, with square cross-sections perpendicular to the x-axis.
Your turn1 of 2
Find the volume of a solid whose base is bounded by y = 4x2 and y = 6, with square cross-sections perpendicular to the x-axis.6.2 Volumes with Triangular and Semicircular Cross-Sections
- How it worksHow do you write the area of an equilateral triangle or a semicircle in terms of the same variable that describes the base?
- Common mistakeWhy doesn't a cross-section's shape need to match the shape of the solid's base at all?
- Worked exampleFind the volume of a solid whose base is the region under y = square root of x from 0 to 4, with semicircular cross-sections perpendicular to the x-axis.
Your turn1 of 2
Find the volume of a solid whose base is the region under y = 4·square root of x from 0 to 6, with semicircular cross-sections perpendicular to the x-axis (diameter equal to the region's height at each x).6.2 The Disk Method
- How it worksWatch a two-dimensional region actually revolve around an axis and sweep out a three-dimensional solid.
- Worked exampleFind the volume of the solid formed by revolving y = square root of x around the x-axis from x = 0 to x = 4 using disks.
- Worked exampleFind the volume of the solid formed by revolving y = 4 - x2 around the x-axis from x = -2 to x = 2 using disks.
- Common mistakeWhy isn't the radius in the disk method always just the function's value, regardless of which axis you revolve around?
- Going furtherWhat happens to the disk method's setup when the region is revolved around the y-axis instead of the x-axis?
Your turn1 of 2
A region under y = 4·square root of x is revolved around the x-axis. Write the disk's cross-sectional area A(x), the integrand for the volume integral, as a function of x.6.2 The Washer Method
- How it worksWatch a washer's hole appear as the inner curve is subtracted from the outer curve before the region revolves.
- Worked exampleFind the volume of the solid formed by revolving the region between y = x2 and y = 2x around the x-axis using washers.
- Going furtherWhat happens to the washer method's setup when the axis of revolution is a horizontal line other than the x-axis?
- Worked exampleFind the volume of the solid formed by revolving the region between y = square root of x and y = x/2 around the x-axis using washers.
- Common mistakeWhy doesn't the washer method reduce to the disk method's formula just by ignoring the inner radius entirely?
Your turn1 of 2
The region between y = x2 and y = 4x is revolved around the x-axis. Write the washer's cross-sectional area A(x), the integrand for the volume integral, as a function of x.6.3 Volumes of Revolution: Cylindrical Shells
- How it worksWatch a single cylindrical shell unroll into a flat rectangle whose area gives the shell method its formula.
- Worked exampleFind the volume of the solid formed by revolving the region under y = x2 from x = 0 to x = 2 around the y-axis using shells.
- Common mistakeWhy isn't the shell method's radius measured from the curve itself instead of from the axis of revolution?
Your turn1 of 2
Find the volume of the solid formed by revolving the region under y = 4x2 from x = 0 to x = 4 around the y-axis using shells.6.3 Choosing Disks, Washers, or Shells
- How it worksHow does the axis of revolution and the way the region is bounded decide whether disks, washers, or shells is the fastest method?
- Worked exampleBuild both a shell integral and a washer integral, without evaluating either, for revolving y = x2 from x = 0 to x = 2 around the y-axis.
- Going furtherWhat happens to the difficulty of a volume problem when the axis of revolution is moved from the y-axis to the line x = 3?
Your turn1 of 2
The region under y = 4x2 from x=0 to x=4 is revolved around the y-axis. Find its volume by evaluating a washer integral in terms of y (integrating from y=0 to y=4·42).6.4 Arc Length of a Curve
- How it worksHow does the Pythagorean theorem applied to infinitesimally small steps along a curve build the arc length integral?
- Going furtherWhat happens to the arc length formula when the curve is described as x in terms of y instead of y in terms of x?
- Common mistakeWhy isn't the arc length of a curve just the straight-line distance between its two endpoints?
- Worked exampleFind the arc length of f(x) = x3/2 from x = 0 to x = 4.
Your turn1 of 2
For f(x) = 3x3/2, the arc-length integral is the integral of √(1+(f'(x))2) dx. Write this integrand as a function of x.6.4 Surface Area of a Solid of Revolution
- How it worksHow does revolving a tiny piece of arc length around an axis sweep out a thin ring whose area you can add up?
- Worked exampleFind the surface area generated by revolving y = square root of x from x = 0 to x = 4 around the x-axis.
- Common mistakeWhy isn't the surface area of a solid of revolution the same calculation as its volume?
- Going furtherWhat happens to the surface area formula when the axis of revolution is the y-axis instead of the x-axis?
Your turn1 of 2
For f(x) = 3·square root of x, the surface-area integral is the integral of 2·π·f(x)*√(1+(f'(x))2) dx. Write this integrand as a function of x.6.1 The Average Value of a Function
- How it worksHow does dividing a definite integral by the length of the interval produce a function's true average value?
- Common mistakeWhy isn't the average value of a function the same as the average of its value at the two endpoints?
- Worked exampleFind the average value of f(x) = x2 on the interval from 0 to 3.
Your turn1 of 2
Find the average value of f(x) = 4x2 + 6 on the interval from 0 to 8.5.3 The Mean Value Theorem for Integrals
- How it worksHow does the Mean Value Theorem for Integrals guarantee a point where the function's height matches a rectangle of equal area?
- Worked exampleFind the value guaranteed by the Mean Value Theorem for Integrals for f(x) = x2 on the interval from 0 to 3.
- Common mistakeWhy doesn't the Mean Value Theorem for Integrals guarantee that point sits at the interval's midpoint?
Your turn1 of 2
For f(x) = 4x2 on the interval from 0 to 6, find the value c guaranteed by the Mean Value Theorem for Integrals, where f(c) equals the average value of f.6.5 Recovering Position from Velocity
- How it worksHow does the Net Change Theorem applied to velocity recover an object's displacement over a time interval?
- Worked exampleFind the displacement of an object with velocity v(t) = t2 - 4t from t = 0 to t = 3.
- Common mistakeWhy isn't the displacement of an object always equal to the total distance it traveled?
Your turn1 of 2
An object has velocity v(t) = 4t2 - 6t and initial position s(0) = 4. Find its position function s(t).6.5 Displacement Versus Total Distance Traveled
- How it worksHow does integrating the absolute value of velocity, instead of velocity itself, capture total distance traveled?
- Going furtherWhat happens to the total-distance integral when a velocity function never changes sign on the interval?
- Worked exampleFind the total distance traveled by an object with velocity v(t) = t2 - 4t from t = 0 to t = 3.
Your turn1 of 2
Find the total distance traveled by an object with velocity v(t) = t2 - 3t from t = 0 to t = 8.6.5 Work Done by a Variable Force
- How it worksHow does integrating a changing force over distance turn Hooke's Law into a formula for the work stored in a spring?
- Worked exampleFind the work done stretching a spring 0.4 meters beyond its natural length if a force of 20 N stretches it 0.2 meters, using Hooke's Law.
- Worked exampleFind the work required to pump the water out of a cylindrical tank of radius 2 meters and height 6 meters through its top.
- Common mistakeWhy isn't the work done stretching a spring simply the final force multiplied by the total distance stretched?
Your turn1 of 2
A force of 22 N stretches a spring 0.36 meters beyond its natural length. Using Hooke's Law, find the work W(x) done stretching the spring x meters beyond its natural length.6.5 Hydrostatic Force on a Submerged Plate
- How it worksHow does integrating pressure, which grows with depth, over a plate's area build up the total hydrostatic force?
- Worked exampleFind the hydrostatic force on a vertical rectangular plate 4 meters wide with its top edge 2 meters below the surface and its bottom edge 6 meters below.
- Going furtherWhat happens to the hydrostatic force on a plate when it is tilted instead of held vertically?
- Common mistakeWhy isn't the pressure on a submerged plate the same at every depth across its surface?
Your turn1 of 2
Find the hydrostatic force on a vertical rectangular plate 6 meters wide with its top edge 4 meters below the surface, as a function of the depth d of its bottom edge. Use a weight density for water of 9800 N per cubic meter.6.6 Center of Mass of a Thin Rod or Flat Region
- How it worksHow does weighting each thin slice of a region by both its position and its mass locate the balance point?
- Common mistakeWhy isn't the center of mass of a region always the same as its geometric centroid when the density varies?
- Worked exampleFind the center of mass of a thin rod lying on the interval from 0 to 4 with density function rho(x) = x + 1.
- Going furtherWhat happens to a flat region's center of mass when all of its mass gets pushed toward one edge?
Your turn1 of 2
Find the center of mass of a thin rod on the interval from 0 to L with density function rho(x) = 4x + 4, as a function of the rod's length L.6.8 Exponential Growth
- How it worksHow does solving the differential equation dy/dt equals ky produce the exponential growth formula y = y0·ekt?
- Common mistakeWhy isn't a quantity growing at 10 percent per year the same as a quantity growing by a constant amount each year?
- Worked exampleFind how long it takes a population of 500 bacteria growing at a continuous rate of 8 percent per hour to double.
Your turn1 of 2
A population of 727 grows continuously at a rate of 0.104 per hour. Find how long it takes to grow to 5 times its original size.6.8 Exponential Decay and Half-Life
- How it worksHow does the same exponential model that drives growth flip its sign to drive decay and produce a half-life formula?
- Worked exampleFind the half-life of a substance that decays from 80 grams to 65 grams in 10 years.
- Worked exampleFind how much of a 200-gram sample with a half-life of 5 years remains after 15 years.
- Common mistakeWhy doesn't a substance with a half-life of 5 years ever actually reach zero mass?
Your turn1 of 2
A substance decays from 85 grams to 36 grams in 19 years. Find its half-life.5.3 How the Accumulation Function Connects Back to Its Own Derivative
- How it worksWatch the accumulation function's slope at each point rise and fall to match the height of the integrand directly beneath it.
- Common mistakeWhy isn't a graph of the accumulation function simply a rescaled copy of the original integrand's graph?
- Ties togetherHow does connecting a function, its accumulation function, and its derivative graph tie together everything differentiation and integration do?
Your turn1 of 2
Let A(x) = the integral of (4t + 6) from 0 to x, the accumulation function for f(t)=4t+6. Find A'(x).