Unit 4: Multiple Integration
A double integral is a volume under a surface, re-swept the other way, mapped through polar grids, then stretched by a Jacobian before tripling into solids.
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5.1 Double Integrals over Rectangular Regions
- How it worksHow does a Riemann sum over a rectangular grid turn into a double integral as the grid gets finer?
- Worked exampleBuild the double Riemann sum estimate for the volume under z = x + y over the rectangle [0,2] x [0,2] using a 2x2 grid.
- Common mistakeWhy doesn't a double integral require you to pick an order before you can add up the little box volumes?
Your turn1 of 2
Find the double integral of x + 4y over the rectangle [0,4] x [0,5].5.1 A Double Integral as the Volume Under a Surface
- How it worksHow does slicing the solid under a surface into thin slabs turn a volume problem into an iterated integral?
- Worked exampleFind the volume under z = 4 - x2 - y2 over the rectangle [0,1] x [0,1].
- Going furtherWhat happens to this volume interpretation once the surface dips below the xy-plane somewhere in the region?
- Common mistakeWhy doesn't a negative value for a double integral mean the volume it represents is somehow negative?
Your turn1 of 2
Find the volume under z = 8 - x2 - y2 over the rectangle [0,1.47] x [0,1.9].5.1 Iterated Integrals and Fubini's Theorem
- How it worksHow does Fubini's theorem let you swap the order of an iterated integral over a rectangle without changing the answer?
- Worked exampleFind the iterated integral of x2 y over y from 0 to 2 and x from 0 to 3.
- Worked exampleFind the same integral of x2 y over the same rectangle, integrating with respect to x first instead.
- Common mistakeWhy doesn't Fubini's theorem guarantee you can swap the order of integration once the region isn't a plain rectangle?
Your turn1 of 2
Find the iterated integral of 4x2y over y from 0 to 5 and x from 0 to 4.5.2 Double Integrals over General Regions
- How it worksHow do the inner integral's limits become functions of the outer variable when a region has curved boundaries?
- Worked exampleFind the double integral of xy over the region bounded by y = x2 and y = x for x between 0 and 1.
- Common mistakeWhy can't a double integral's limits always be written as four fixed numbers?
- Worked exampleFind the double integral of x over the region bounded by y = 0, y = x2, and x = 2.
Your turn1 of 2
Find the double integral of xy over the region bounded by y = x2 and y = 3x for x between 0 and 3.5.2 Type I and Type II Regions
- How it worksHow does a Type I region stack vertical strips while a Type II region stacks horizontal ones?
- Worked exampleSketch and describe the region bounded by y = x2 and y = 4 as both a Type I and a Type II region.
- Going furtherWhat happens when a region isn't cleanly Type I or Type II on its own?
- Worked exampleFind the double integral of 1 over the region between y = x and y = x2 by treating it as a Type I region.
Your turn1 of 2
Find the double integral of 1 over the region between y = x and y = 4x2 (for x between 0 and 1/4), treating it as a Type I region.5.2 Switching the Order of Integration
- Common mistakeWhy doesn't switching the order of integration mean you can just swap the numbers in the limits without re-deriving them?
- How it worksHow does re-sweeping the same region with horizontal strips instead of vertical ones change the limits of integration?
- Worked exampleFind the switched order and evaluate the integral of sin(y2) over y from x to 1 and x from 0 to 1.
- Worked exampleSketch the region for the integral of f(x,y) over y from x to 1 and x from 0 to 1, then switch its order.
Your turn1 of 2
Find the value of the integral of sin(2.24y2) over y from x to 1 and x from 0 to 1, by switching the order of integration.5.2 Area of a Planar Region by Double Integration
- How it worksHow does the double integral of 1 over a region collapse into the same area formula a single integral would give?
- Worked exampleFind the area of the region bounded by y = x2 and y = 2x, using a double integral.
- Going furtherWhat changes about finding area by double integration once a region is bounded by three curves instead of two?
Your turn1 of 2
Find the area of the region bounded by y = 3x2 and y = 4x, using a double integral.5.3 Double Integrals in Polar Coordinates
- How it worksHow does an extra factor of r appear in dA once a double integral switches to polar coordinates?
- Worked exampleFind the double integral of x2 + y2 over the disk of radius 3 centered at the origin, using polar coordinates.
- Common mistakeWhy can't you convert a double integral to polar coordinates just by replacing x with r cos(theta) and y with r sin(theta) alone?
Your turn1 of 2
Converting the double integral of x2 + y2 to polar coordinates turns x2+y2 into r2, and dA into r dr dtheta. Write the resulting full integrand r2·r, as a function of r.5.3 Converting a Region to Polar Coordinates for Integration
- Worked exampleFind the polar limits for the region between x2 + y2 = 1 and x2 + y2 = 4 in the first quadrant.
- Worked exampleFind the double integral of e−(x^2+y^2) over the entire plane, using polar coordinates.
- Going furtherWhat happens to the polar limits of integration once a region is a cardioid instead of a circle?
- Common mistakeWhy doesn't every circular-looking region convert into a rectangle in the r-theta plane?
Your turn1 of 2
Find the double integral of e−2.94(x^2+y^2) over the entire plane, using polar coordinates.5.2 Surface Area of a Graph z = f(x, y)
- How it worksHow do the two partial derivatives of f combine into the stretch factor inside a surface area integral?
- Worked exampleFind the surface area of the part of the plane z = 2x + 2y + 1 that lies above the unit square [0,1] x [0,1].
- Worked exampleFind the surface area of the part of the paraboloid z = x2 + y2 that lies below the plane z = 4.
- Going furtherWhat happens to the surface area integral's stretch factor as a surface gets steeper and steeper?
Your turn1 of 2
Find the surface area of the part of the plane z = 4x + 4y + 4 that lies above the rectangle [0,1.2] x [0,0.66].5.2 Average Value of a Function Over a Region
- How it worksHow does dividing a double integral by a region's area turn a total into an average value?
- Worked exampleFind the average value of f(x, y) = x + y over the rectangle [0,2] x [0,4].
- Common mistakeWhy isn't the average value of a function over a region just the average of its values at the corners?
- Going furtherWhat happens to a function's average value over a region as that region shrinks down to a single point?
Your turn1 of 2
Find the average value of f(x, y) = x + 4y over the rectangle [0,4] x [0,6].5.6 Mass of a Planar Lamina from Density
- How it worksHow does integrating a density function over a region add up mass the same way integrating 1 adds up area?
- Worked exampleFind the mass of the lamina occupying the square [0,1] x [0,1] with density rho(x,y) = x + y.
- Going furtherWhat happens to the mass integral once the density function is constant across the whole lamina?
- Common mistakeWhy doesn't doubling a lamina's density function automatically double the location of its center of mass?
Your turn1 of 2
Find the mass of the lamina occupying the rectangle [0,4] x [0,2] with density rho(x,y) = 4x + 4y.5.6 Moments and the Center of Mass
- How it worksHow do the moments about the x- and y-axes get divided by the total mass to locate the center of mass?
- Worked exampleFind the center of mass of the lamina on [0,2] x [0,1] with density rho(x,y) = x.
- Common mistakeWhy isn't the center of mass of a lamina always the same as its plain geometric center?
Your turn1 of 2
Find the x-coordinate of the center of mass of the lamina on [0,4] x [0,6] with density rho(x,y) = 4x.5.6 Moments of Inertia
- How it worksHow does moment of inertia weight each bit of mass by the square of its distance from the axis?
- Worked exampleFind the moment of inertia about the x-axis of the lamina on [0,1] x [0,1] with density rho(x,y) = 1.
- Ties togetherHow does the moment of inertia integral extend the same weighting idea used to find the center of mass?
Your turn1 of 2
Find the moment of inertia about the x-axis of the lamina on [0,4] x [0,5] with constant density rho(x,y) = 4.5.6 Symmetry Shortcuts in Center of Mass Calculations
- How it worksHow does an odd density function paired with a symmetric region force one of the moment integrals to vanish?
- Worked exampleFind the x-coordinate of the center of mass of a semicircular lamina of radius 2 with constant density, using symmetry.
- Common mistakeWhy doesn't a symmetric region alone guarantee a shortcut if the density function isn't symmetric too?
Your turn1 of 2
Find the x-coordinate of the center of mass of a semicircular lamina of radius 7 (flat side along the y-axis, bulging into x > 0) with constant density, using symmetry.5.6 Center of Mass and Moments of a Solid Region
- How it worksHow do the moments about the three coordinate planes get divided by total mass to locate a solid's center of mass?
- Worked exampleFind the center of mass of the solid box [0,2] x [0,1] x [0,1] with density rho(x,y,z) = x.
- Going furtherWhat happens to a solid's center of mass calculation once its density is constant throughout?
Your turn1 of 2
Find the x-coordinate of the center of mass of the solid box [0,4] x [0,6] x [0,2] with density rho(x,y,z) = 4x.5.4 Triple Integrals over a Box
- How it worksHow does a triple integral over a rectangular box reduce to three ordinary integrals done one variable at a time?
- Worked exampleFind the triple integral of xyz over the box [0,1] x [0,2] x [0,3].
- Common mistakeWhy doesn't the order you integrate x, y, and z in matter for a triple integral over a box?
- Worked exampleFind the triple integral of x2 + y2 + z2 over the box [0,1] x [0,1] x [0,1].
Your turn1 of 2
Find the triple integral of 3xyz over the box [0,3] x [0,4] x [0,2].5.4 Triple Integrals over General Regions
- How it worksHow do the innermost limits of a triple integral become functions of the two outer variables for a curved solid?
- Worked exampleFind the volume of the solid bounded above by z = 4 - x2 - y2 and below by z = 0.
- Going furtherWhat happens to setting up a triple integral's limits once a solid's shadow on the xy-plane isn't simple?
- Worked exampleFind the volume of the solid bounded by z = x + y, z = 0, x = 0, y = 0, and x + y = 1.
Your turn1 of 2
Find the volume of the solid bounded above by z = 7 - x2 - y2 and below by z = 0.5.5 Triple Integrals in Cylindrical Coordinates
- How it worksHow does an extra factor of r show up in dV once a triple integral converts to cylindrical coordinates?
- Worked exampleFind the volume of the solid inside the cylinder x2 + y2 = 4 and between z = 0 and z = 5, using cylindrical coordinates.
- Worked exampleFind the mass of the solid cylinder x2 + y2 ≤ 4, 0 ≤ z ≤ 3 with density rho(x,y,z) = z, using cylindrical coordinates.
- Common mistakeWhy doesn't converting a triple integral to cylindrical coordinates mean the z-limits also have to be rewritten in r and theta?
Your turn1 of 2
Find the volume of the solid inside the cylinder x2 + y2 = 42 and between z = 0 and z = 7, using cylindrical coordinates.5.5 Triple Integrals in Spherical Coordinates
- How it worksHow does the factor rho2 sin(phi) appear in dV once a triple integral converts to spherical coordinates?
- Worked exampleFind the volume of the solid sphere of radius 2, using a triple integral in spherical coordinates.
- Worked exampleFind the volume of the region above the cone phi = π/4 and inside the sphere rho = 2, using spherical coordinates.
- Common mistakeWhy isn't phi measured from the xy-plane the way latitude is, instead of from the positive z-axis?
- Going furtherWhat happens to the spherical volume element once phi ranges only from 0 to π/2 instead of 0 to π?
Your turn1 of 2
In converting a triple integral to spherical coordinates, write the volume element's integrand rho2 sin(phi), as a function of rho and phi.5.5 Choosing the Right Coordinate System for a Triple Integral
- Ties togetherHow do the symmetries that favor cylindrical coordinates differ from the ones that favor spherical coordinates?
- Worked exampleFind which coordinate system best sets up the volume integral for the solid region between two concentric spheres of radius 1 and 2.
- Going furtherWhat happens to a triple integral's difficulty once a solid has an axis of symmetry but isn't centered at the origin?
Your turn1 of 2
Find the volume of the solid region between two concentric spheres of radius 3 and 8 (with 8 > 3).5.7 Change of Variables and the Jacobian in Two Variables
- How it worksHow does the Jacobian determinant measure exactly how a small patch of area changes size under a coordinate transformation?
- Worked exampleFind the Jacobian of the transformation x = u + v, y = u - v.
- Common mistakeWhy isn't the Jacobian just the product of dx/du and dy/dv?
- Going furtherWhat happens to the Jacobian of a linear transformation once the transformation is just a rotation?
Your turn1 of 2
Write the Jacobian of the transformation x = au + bv, y = cu + dv, as a function of a, b, c, and d.5.7 The Jacobian as a Local Area-Stretch Factor
- How it worksHow does the absolute value of the Jacobian at a point tell you the local stretching or shrinking factor there?
- Worked exampleFind the double integral of (x+y) ex-y over the square with vertices (0,0), (1,1), (2,0), (1,-1), using u = x+y, v = x-y.
- Going furtherWhat happens to a region's mapped area at a point where the Jacobian equals zero?
- Ties togetherHow does this local stretch factor mirror the way a cross product's magnitude measures area stretch for a parametric surface?
Your turn1 of 2
A transformation from (x,y) to (u,v) has Jacobian determinant j = partial(u,v)/partial(x,y) = 6 at a point. Find the local area-stretch factor for the REVERSE transformation from (u,v) back to (x,y), |partial(x,y)/partial(u,v)|.5.7 Mapping an Ellipse to a Circle with a Change of Variables
- How it worksHow does the substitution x = au, y = bv stretch a unit circle in the uv-plane into an ellipse in the xy-plane?
- Worked exampleFind the double integral of 1 over the ellipse x2/4 + y2/9 ≤ 1, using the substitution x = 2u, y = 3v.
- Going furtherWhat happens to the Jacobian factor once the ellipse is also rotated, not just stretched along the axes?
Your turn1 of 2
Write the Jacobian of the substitution x = Au, y = Bv, as a function of A and B.5.7 Change of Variables in Triple Integrals
- How it worksHow does the three-variable Jacobian generalize the area-stretch idea into a volume-stretch factor?
- Worked exampleShow that converting to spherical coordinates gives dV = rho2 sin(phi) d rho d phi d theta by computing the Jacobian determinant.
- Ties togetherHow does this general change-of-variables formula explain why cylindrical and spherical coordinates each carry their own extra factor in dV?
Your turn1 of 2
Write the Jacobian of the transformation x = au, y = bv, z = cw, as a function of a, b, and c.5.3 Finding Area in Polar Coordinates with a Double Integral
- How it worksHow does integrating r dr dtheta over a polar region recover the same area a single polar integral would give?
- Worked exampleFind the area enclosed by one petal of r = cos(2 theta), using a double integral in polar coordinates.
- Worked exampleFind the area inside the circle r = 2 and outside the circle r = 1, using a double integral in polar coordinates.
Your turn1 of 2
Find the area enclosed by one petal of r = 4cos(4 theta), using a double integral in polar coordinates.