Unit 3: Existence, Uniqueness, and Qualitative Behavior
When a solution is guaranteed to exist and be the only one, and how a phase line predicts a solution's fate without ever solving the equation.
8 topics · 29 questions
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2.8 Existence and Uniqueness for First-Order Equations
- How it worksHow do continuity conditions on f and its partial derivative guarantee one solution through a starting point?
- Common mistakeWhy doesn't the existence and uniqueness theorem guarantee a solution exists for all future time?
- Going furtherWhat happens to a solution's guaranteed interval of existence as the starting point moves closer to where f blows up?
- Worked exampleShow that the equation y' = y2, y(0) = 1 satisfies the existence and uniqueness theorem's hypotheses near t = 0.
Your turn1 of 2
For y' = y2, y(0) = 2, the exact solution is y = y0/(1 - y0 t). Find y(t) at t = 0.23.2.8 Why Solution Curves of the Same Equation Never Cross
- How it worksHow does uniqueness at every point force two nearby solution curves to stay separated forever?
- Worked exampleShow that y = ex and y = ex + 1 never cross by comparing them as solutions of y' = y.
- Going furtherWhat would it mean physically if two different cooling curves for the same object actually did cross?
Your turn1 of 2
For y' = y, compare the two solutions y1 = 3ex and y2 = 8ex. Find the value of y2(x) - y1(x) at x = 1.61.2.8 When the Uniqueness Theorem's Conditions Fail
- How it worksHow does a vertical tangent in y1/3 at zero break the smoothness the uniqueness theorem needs?
- Worked exampleShow that both y = 0 and y = (2x/3)3/2 solve y' = y1/3 with y(0) = 0.
- Common mistakeWhy doesn't finding one valid solution to an initial value problem guarantee it's the only one?
Your turn1 of 2
The nonzero solution branch of y' = 3y1/3, y(0) = 0, is y = ((2k/3)x)1.5. Find y(2.12).2.5 Autonomous Equations and Equilibrium Solutions
- How it worksHow do you find the equilibrium solutions of an autonomous equation just by looking at where the rate is zero?
- Worked exampleFind the equilibrium solutions of dy/dt = y(y - 3)(y + 2).
- Going furtherWhat happens to a solution of an autonomous equation that starts exactly on one of its equilibrium values?
- Common mistakeWhy doesn't an autonomous equation's solution curve look identical no matter which two equilibria it starts between?
Your turn1 of 2
Find the sum of the three equilibrium solutions of dy/dt = y(y - 5)(y + 5).2.5 The Phase Line and Flow Arrows
- How it worksHow do the signs of f(y) between consecutive equilibria turn into arrows pointing up or down the phase line?
- How it worksHow does reading the arrows on either side of an equilibrium tell you what nearby solutions do over time?
- Going furtherWhat happens on the phase line when two equilibria merge into one as a parameter changes?
Your turn1 of 2
For dy/dt = (y - 2)(y - 8), find the value of dy/dt at y = 5.2.5 Stable, Unstable, and Semistable Equilibria
- How it worksHow do the arrows on both sides of an equilibrium determine whether it's stable, unstable, or semistable?
- Worked exampleFind the stability of each equilibrium of dy/dt = y(1 - y)(y - 2).
- Common mistakeWhy doesn't a stable equilibrium attract every single solution on the entire phase line?
- Going furtherWhat happens to a solution that starts just barely on the unstable side of a semistable equilibrium?
Your turn1 of 2
For dy/dt = (2 - y)(y - 8) with a < b, the right-hand side is f(y). Find f'(2), the derivative of f evaluated at the equilibrium y = a. (A positive value means solutions move away — the equilibrium is unstable there.)2.5 The Logistic Equation's Phase Line
- How it worksHow do the two equilibria at 0 and the carrying capacity K show up on the logistic equation's phase line?
- Worked exampleFind the equilibria and their stability for dP/dt = 0.5P(1 - P/200).
- Going furtherWhat happens to the logistic phase line when the carrying capacity K is cut in half?
- Common mistakeWhy doesn't a population starting above the carrying capacity K keep growing past it instead of shrinking back down?
Your turn1 of 2
For the logistic equation dP/dt = 0.687P(1 - P/360), find the value of dP/dt when P = 360/2.2.5 Bifurcations as a Parameter Changes
- How it worksHow does plotting equilibria against a changing parameter build a bifurcation diagram?
- Worked exampleFind the bifurcation value of h in dy/dt = y2 - h and describe what happens to the equilibria as h crosses it.
- Going furtherWhat happens to the phase line just before and just after a saddle-node bifurcation occurs?
- Ties togetherHow does a bifurcation diagram's curve of equilibria connect to the phase lines you'd draw at each fixed parameter value?
Your turn1 of 2
Find the bifurcation value h·of the parameter h in dy/dt = y2 - 5y - h, the value at which the number of equilibria changes.