Unit 8: Mechanical and Electrical Vibrations
A mass on a spring, damped, forced, and pushed to resonance — the three root cases from Unit 6 made physical, plus the RLC circuit that obeys the same equation.
10 topics · 36 questions
Each topic is a path, not a menu: work down it in order and every question builds on the one above. Click any of them to watch the answer draw itself.
3.7 Setting Up the Spring-Mass Equation
- How it worksHow do Hooke's law and Newton's second law combine into m x'' + gamma x' + k x = F(t)?
- Worked exampleBuild the differential equation for a 2 kg mass on a spring with spring constant 8 N/m and no damping or forcing.
- Going furtherWhat happens to the spring-mass equation once the mass hangs so that gravity also stretches the spring?
- Common mistakeWhy doesn't a stiffer spring, meaning a bigger spring constant k, automatically mean slower oscillation?
Your turn1 of 2
Build the differential equation for a 4 kg mass on a spring with spring constant 15 N/m and no damping or forcing: m x'' + kx = 0. Find the natural frequency omega0 = √(k/m).3.7 Free Undamped Vibrations
- How it worksHow does the natural frequency omega0 = √(k/m) fall straight out of the spring-mass equation's characteristic roots?
- Worked exampleFind the natural frequency and period of a 4 kg mass on a spring with k = 16 N/m.
- Common mistakeWhy doesn't pulling the mass back farther before releasing it change how fast it oscillates?
Your turn1 of 2
Find the period T = 2·π/omega0 of a 4 kg mass on a spring with k = 18 N/m.3.7 Solving a Free Undamped Vibration Problem
- Worked exampleSolve x'' + 9x = 0 for a mass released from x(0) = 2 with zero initial velocity, and write the answer as R cos(omega t - delta).
- Worked exampleFind the amplitude R and phase angle delta for x(0) = 1, x'(0) = 3 on x'' + 4x = 0.
- Going furtherWhat happens to the amplitude R when the same mass is released from rest but from twice the initial displacement?
Your turn1 of 2
Find the amplitude R = √(x02 + (v0/omega)2) for x'' + 42 x = 0 with x(0) = 3 and x'(0) = 6.3.8 The Three Cases of Free Damped Vibration
- How it worksHow does the sign of gamma2 - 4mk split damped vibration into three completely different behaviors?
- Worked exampleFind whether x'' + 5x' + 4x = 0, x'' + 4x' + 4x = 0, and x'' + x' + 4x = 0 are overdamped, critically damped, or underdamped.
- Going furtherWhat happens to a mass's motion as the damping coefficient gamma is slowly increased from zero past the critical value?
- Ties togetherHow do the three damping cases here connect to the same three root cases from a constant-coefficient characteristic equation?
Your turn1 of 2
For m x'' + 7x' + 5x = 0 with m = 2, find the discriminant gamma2 - 4mk.3.8 Underdamped Motion
- How it worksHow does an exponentially decaying envelope multiplying a cosine produce underdamped motion's shrinking oscillations?
- Worked exampleSolve x'' + 2x' + 5x = 0 with x(0) = 1, x'(0) = 0, and identify the decay rate and quasi-frequency.
- Common mistakeWhy isn't the quasi-period of underdamped motion the same as the natural period with no damping at all?
- Going furtherWhat happens to underdamped motion's quasi-frequency as the damping coefficient climbs closer to the critical value?
Your turn1 of 2
Solve x'' + (2·2)x' + (22+42)x = 0 with x(0) = 4 and x'(0) = 0. (Its characteristic roots are -2 plus or minus 4i.) Find x(t).3.8 Critically Damped and Overdamped Motion
- How it worksHow does a repeated real root produce the fastest possible non-oscillating return in critically damped motion?
- Worked exampleSolve x'' + 4x' + 4x = 0 with x(0) = 1, x'(0) = 1, and describe the motion.
- Common mistakeWhy isn't critically damped motion just an overdamped motion that happens to be a little bit faster?
Your turn1 of 2
Solve x'' + (3·2)x' + 32 x = 0 with x(0) = 2 and x'(0) = 4, given that -3 is a repeated root. Find x(t).3.9 Forced Vibrations Without Damping and Beats
- How it worksHow does adding two cosines with close but different frequencies produce the slow beat envelope on top of the fast oscillation?
- Worked exampleSolve x'' + 25x = 4 cos(4t) with x(0) = 0, x'(0) = 0, and identify the beat frequency.
- Going furtherWhat happens to the beat pattern as the forcing frequency is dialed closer and closer to the natural frequency?
Your turn1 of 2
For x'' + 5.2272 x = 8cos(4.084t) with x(0)=0, x'(0)=0 (w is not equal to w0), find the beat frequency (w0-w)/2.3.9 Resonance in Forced, Damped Vibrations
- How it worksHow does the steady-state amplitude formula spike as the forcing frequency approaches the system's natural frequency?
- Worked exampleFind the forcing frequency that maximizes the steady-state amplitude of x'' + 2x' + 25x = F0 cos(omega t).
- Common mistakeWhy doesn't resonance require zero damping to make a system's amplitude climb dramatically?
- Going furtherWhat happens to the resonance peak's height and sharpness as the damping coefficient shrinks toward zero?
- Ties togetherHow does mechanical resonance here connect to the amplitude blow-up an RLC circuit shows at its resonant frequency?
Your turn1 of 2
For x'' + 3x' + 23x = F0 cos(omega t), find the forcing frequency omegar = √(k - gamma2/2) that maximizes the steady-state amplitude.3.7 The RLC Circuit as a Mechanical Analogy
- How it worksHow do inductance, resistance, and inverse capacitance play the roles of mass, damping, and spring stiffness?
- Worked exampleFind the differential equation for charge in an RLC circuit with L = 1 henry, R = 4 ohms, and C = 0.25 farad, with no applied voltage.
- Going furtherWhat happens to the circuit's behavior when the resistance R is increased past the critical damping value?
- Worked exampleFind whether an RLC circuit with L = 1 henry, R = 6 ohms, and C = 0.25 farad is overdamped, critically damped, or underdamped.
Your turn1 of 2
For an RLC circuit with L = 2 henry, R = 6 ohms, and C = 0.473 farad, find the discriminant R2 - 4L/C that determines its damping case.3.8 Energy in a Vibrating System
- How it worksHow does damping steadily drain energy out of a vibrating system until it settles at equilibrium?
- Worked exampleFind the total energy of a 1 kg mass on a spring with k = 9 N/m at x(0) = 1, x'(0) = 0, assuming no damping.
- Going furtherWhat happens to the energy-versus-time graph of a damped oscillator compared to an undamped one?
Your turn1 of 2
Find the total energy E = (1/2)mv2 + (1/2)kx2 of a 2 kg mass on a spring with k = 11 N/m, at x(0) = 3, x'(0) = 1, assuming no damping.