Unit 3: Partial Derivatives and the Gradient
Slicing a surface to turn slopes into single-variable calculus, then bundling every slope at a point into one arrow: the gradient.
13 topics · 45 questions
Each topic is a path, not a menu: work down it in order and every question builds on the one above. Click any of them to watch the answer draw itself.
3.1 Limits in Several Variables
- How it worksHow does testing several different paths toward a point expose a two-variable limit that does not exist?
- Common mistakeWhy isn't a two-variable limit guaranteed to exist just because it exists along the x-axis and along the y-axis?
- Worked exampleFind the limit of (x2 - y2)/(x - y) as (x, y) approaches (2, 2).
Your turn1 of 2
Find the limit of (x2 - y2)/(x - y) as (x, y) approaches (3, 3).3.2 Continuity and the Path Test for Limits
- How it worksHow does comparing the paths y = 0 and y = x expose a limit that depends on the direction of approach?
- Worked exampleShow that the limit of xy/(x2 + y2) as (x, y) approaches (0, 0) does not exist by comparing the paths y = 0 and y = x.
- Going furtherWhat happens to the path test when you approach along a curved path like y = x2 instead of a straight line?
Your turn1 of 2
Along the straight path y = k·x, the ratio xy/(x2+y2) simplifies to a constant that depends on k. Write that constant as a function of k.3.3 Partial Derivatives
- How it worksHow does holding y fixed and differentiating with respect to x alone produce the partial derivative fx?
- Common mistakeWhy doesn't fx measure the surface's steepness in every direction, only in the one direction where y stays fixed?
- Worked exampleFind the partial derivatives fx and fy for f(x, y) = x2 y + sin(y).
Your turn1 of 2
Find fx for f(x, y) = 4x2·y + sin(y), as a function of x and y.3.4 Higher-Order Partial Derivatives and Clairaut's Theorem
- How it worksHow do you compute the mixed partial derivatives f_xy and f_yx from a function of two variables?
- Common mistakeWhy isn't it true for every possible function that f_xy always equals f_yx?
- Worked exampleFind f_xy and f_yx for f(x, y) = x3 y2 + exy, and confirm they agree.
- Going furtherWhat happens to the equality of f_xy and f_yx at a point where those mixed partials are not continuous?
Your turn1 of 2
Find f_xy for f(x, y) = x3·y2 + e3·x·y, as a function of x and y.3.5 The Chain Rule in Several Variables
- How it worksHow does the multivariable chain rule add up the contributions from every intermediate variable's own rate of change?
- Worked exampleFind dz/dt for z = x2 + y2, where x = cos(t) and y = sin(t).
- Going furtherWhat happens to the chain rule formula when z depends on x and y, which each depend on two new variables s and t instead of one?
Your turn1 of 2
Let z = x2·y, x = 3·t, y = 3·t2. Find dz/dt using the chain rule, as a function of t.3.6 Implicit Differentiation in Several Variables
- How it worksHow do the partial derivatives of F(x, y) combine into the formula dy/dx = -Fx / Fy for an implicit curve?
- Common mistakeWhy doesn't implicit differentiation require solving the equation for y before you can differentiate it?
- Worked exampleFind dy/dx at the point (1, 1) on the curve x3 + y3 = 2 using implicit differentiation.
Your turn1 of 2
The curve x3 + 4·y3 = 13 defines y implicitly as a function of x. Find dy/dx, as a function of x and y.3.7 Tangent Planes to a Surface
- How it worksHow do the two partial derivatives at a point combine into the normal vector that defines the tangent plane?
- Worked exampleFind the equation of the tangent plane to z = x2 + y2 at the point (1, 2, 5).
- Going furtherWhat happens to the tangent plane at a point where both partial derivatives equal zero?
Your turn1 of 2
Find the tangent plane to z = x2 + 4·y2 at the point (1, 3, z0), where z0 = x02 + 4·y02. Write that tangent plane's z as a function of x and y.3.8 Linearization and the Differential
- How it worksHow does the tangent plane's equation double as a linear approximation formula near the point of tangency?
- Worked exampleFind the linearization-based estimate of the square root of (4.022 + 3.012) near the point (4, 3).
- Common mistakeWhy doesn't the linear approximation stay accurate far away from the point where it was built?
Your turn1 of 2
Linearize f(x, y) = 4·x2 + 4·y2 at the point (3, -2). Write the linearization L(x, y) as a function of x and y.3.9 The Gradient Vector
- How it worksHow do the partial derivatives fx and fy stack together into the gradient vector at a point?
- Worked exampleFind the gradient of f(x, y) = x2 y + 3y at the point (2, 1).
- How it worksHow does the gradient vector at a point always end up perpendicular to the level curve passing through that same point?
- Common mistakeWhy doesn't the gradient point toward the function's maximum value, only toward the steepest way uphill from where you stand?
- Going furtherWhat happens to the gradient vector's length at a point where the level curves bunch tightly together?
Your turn1 of 2
Find the y-component of the gradient of f(x, y) = 4·x2·y + 4·y, as a function of x.3.10 Directional Derivatives
- How it worksHow does taking the dot product of the gradient with a unit direction vector produce the directional derivative?
- Common mistakeWhy does the directional derivative formula require the direction vector to be a unit vector before you use it?
- Worked exampleFind the directional derivative of f(x, y) = x2 + xy at (1, 2) in the direction of the vector <3, 4>.
- Going furtherWhat happens to the directional derivative as the chosen direction rotates all the way around to point opposite the gradient?
Your turn1 of 2
Find the directional derivative of f(x, y) = 4·x2·y in the direction (4, 6), as a function of x and y.3.11 The Gradient as the Direction of Steepest Ascent
- How it worksHow does maximizing the dot product of the gradient with a unit vector prove the gradient points in the steepest-ascent direction?
- Worked exampleFind the direction of steepest ascent for f(x, y) = x2 + y2 at the point (3, 4).
- Ties togetherWhy is the gradient perpendicular to a level curve and also the normal vector of the tangent plane?
Your turn1 of 2
For f(x, y) = 4·x2 + 4·y2, find the x-component of the unit vector pointing in the direction of steepest ascent, as a function of x and y.3.12 The Gradient in Three Variables and the Normal to a Level Surface
- How it worksHow does the gradient of F(x, y, z) at a point become the normal vector to the level surface F = c passing through that point?
- Worked exampleFind the normal vector to the level surface x2 + y2 + z2 = 9 at the point (0, 0, 3), using the gradient of F(x, y, z) = x2 + y2 + z2.
- Common mistakeWhy isn't the gradient of a three-variable function itself a vector lying tangent to the level surface at that point?
- Going furtherWhat happens to the gradient-as-normal-vector idea at a sharp point of a level surface, like the tip of a cone?
Your turn1 of 2
For F(x, y, z) = 4·x2·y + 4·y·z, find the x-component of grad F (the normal vector to the level surface F = k), as a function of x and y.3.13 Tangent Lines to the Intersection of Two Surfaces
- How it worksHow does taking the cross product of the two surfaces' gradient vectors at a point produce the tangent direction to their curve of intersection?
- Worked exampleFind the tangent line direction to the curve of intersection of x2 + y2 + z2 = 3 and x + y + z = 3 at the point (1, 1, 1).
- Common mistakeWhy isn't the tangent line to a curve of intersection simply the average of the two surfaces' individual normal vectors?
- Ties togetherHow does taking the cross product of two gradient vectors reuse the same cross-product idea from vector geometry?
Your turn1 of 2
Surfaces F(x, y, z) = 4·x2 + y2 + z2 = k and G(x, y, z) = x + y + z = m intersect in a curve. Find the z-component of grad F x grad G (the curve's tangent direction), as a function of x and y.