AP® Calculus AB · Unit 8 · Topic 8.5

Finding the Area Between Curves Expressed as Functions of y

When a region is bounded by sideways-opening curves, slice it horizontally instead of vertically: integrate (right x minus left x) with respect to y over the y-values where the curves meet.

Area between curves always comes from stacking thin strips and adding them up. Usually you slice vertically: strips of height (top minus bottom), integrated in x. But some regions open sideways — bounded by a curve like x = y2, which fails the vertical line test and can't be written as a single function of x without splitting the region into pieces. Turn the slices on their side. Now each strip has width (right minus left), stretches a tiny bit in the y direction, and you integrate with respect to y instead.

The mechanism mirrors the vertical case exactly, just swapped. Find where the curves meet by setting their x-expressions equal and solving for y — these become your limits of integration. Then integrate (x_right(y) - x_left(y)) dy between those y-values. Take x = y2 and x = y + 2: setting y2 = y + 2 gives y2 - y - 2 = 0, so y = -1 and y = 2. On that interval the line sits to the right of the parabola, so the area is the integral from -1 to 2 of ((y+2) - y2) dy.

The real skill is deciding which way to slice before you integrate anything. Look at the picture: if vertical lines cut the region in one continuous piece, slice in x; if horizontal lines do, slice in y. This same judgment call resurfaces when you build solids of revolution — choosing to rotate around the x-axis or y-axis, and whether you get discs or washers, depends on exactly this same read of which direction slices the region cleanly.

Key terms

Horizontal slice
A thin rectangular strip of width (right x minus left x) and height dy, used to build area when integrating in y.
Right minus left
The setup for horizontal slices: subtract the x-value of the left boundary from the x-value of the right boundary.
Vertical line test
A check for whether a curve is a function of x; if a vertical line hits it more than once, it fails and x = y2-style slicing in y is needed.
Limits of integration in y
The y-values where the two boundary curves intersect, found by setting their x-expressions equal and solving for y.

Watch it explained

  1. How it worksHow do horizontal slices of width right minus left set up an integral in y?
  2. Worked exampleFind the area between x = y2 and x = y + 2 by integrating with respect to y.
  3. Common mistakeWhy isn't integrating in x always possible for a sideways-opening region?
  4. Going furtherWhat tells you at a glance whether to slice vertically or horizontally?
  5. Ties togetherHow does choosing to slice horizontally here reappear when you choose between discs and washers later in the unit?

Check yourself

Your turn1 of 3
Find the area of the region bounded by x = y2 and x = 1y + 5, integrating with respect to y.

End of topic.