AP® Calculus AB · Unit 7 · Topic 7.8
Exponential Models with Differential Equations
When a quantity's rate of change is proportional to its own current amount, solving that differential equation always gives an exponential function y = y0 ekt.
Think about why this must be exponential before you ever solve anything. If dy/dt = ky, then the bigger y gets, the faster it changes, and the faster it changes, the bigger it gets. That feedback loop is exactly what exponential growth or decay means: constant percentage change per unit time, not constant amount of change. A population growing at 4 percent per year adds more actual people each year as it gets bigger, because 4 percent of a bigger number is a bigger number.
To solve dy/dt = ky, separate the variables: dy/y = k dt. Integrate both sides to get ln|y| = kt + C. Exponentiate both sides to undo the natural log: y = ekt+C = eC ekt. Rename the constant eC as y0, the value of y when t = 0, and you get the general solution y = y0 ekt. The sign of k decides everything: positive k means growth, negative k means decay, and y0 sets the starting amount.
This is the payoff of the whole unit. Slope fields let you sketch what a solution to dy/dt = ky looks like without solving anything, and separation of variables is the technique that turns that picture into an exact formula. Exponential models are the most common application you will actually use that technique for: population growth, radioactive decay, cooling objects, compound interest. Once you see y = y0 ekt as the solution to a rate-proportional-to-amount setup, you can recognize it in word problems instantly, even before you touch an integral sign.
Key terms
- differential equation
- An equation relating a function to its own derivative, here dy/dt = ky.
- separation of variables
- A solving technique that collects all y terms with dy and all t terms with dt before integrating.
- half-life
- The fixed time it takes a decaying quantity to drop to half its previous amount.
- growth constant k
- The proportionality constant in dy/dt = ky; positive for growth, negative for decay.
- continuous growth rate
- A percentage rate r applied instantaneously at every moment, giving P(t) = P0 e(r/100)t.
Watch it explained
- How it worksHow does solving dy/dt = ky produce a formula with e raised to kt?
- Worked exampleFind how long a 100 gram sample with a 12 year half-life takes to decay to 25 grams.
- Worked exampleFind the population after 10 years starting at 500 and growing continuously at 4 percent.
- Common mistakeWhy isn't exponential decay ever going to reach exactly zero?
Check yourself
End of topic.