AP® Calculus BC · Unit 7 · Topic 7.9

Logistic Growth: Fastest Growth and the Inflection Point

A logistic population grows fastest not when it's biggest, but when it's exactly half of its carrying capacity. That halfway point is the inflection point of the logistic curve, where dP/dt itself peaks.

Logistic growth follows dP/dt = kP(1-P/K), where K is the carrying capacity. This rate is a function of P, and it's not constant: it's small when P is small, grows as P grows, then shrinks back down as P approaches K. That's because two forces fight each other. The factor P pushes the rate up as the population grows. The factor (1-P/K) pushes the rate down as the population nears capacity, since resources get scarce. Somewhere in between, the product is as large as it can get.

To find that peak, treat dP/dt = kP - (k/K)P2 as a function of P and differentiate with respect to P. Setting d/dP(dP/dt) = k - (2k/K)P equal to zero gives P = K/2. That's the population size where the growth rate itself is maximized. In terms of the P-vs-t graph, this is the inflection point: the S-curve is concave up while P < K/2 (growth is accelerating) and concave down once P > K/2 (growth is decelerating), exactly matching concavity ideas from Unit 5, where sign changes in the second derivative mark inflection points.

This connects logistic growth back to everything learned about using derivatives to analyze graphs. The population curve itself never has a max in the middle - it keeps climbing toward K - but its slope does. Recognizing that 'fastest growth' means 'maximum dP/dt', not 'maximum P', is what ties this topic to the broader toolkit of optimizing a function by studying its derivative.

Key terms

Carrying capacity (K)
The maximum population size an environment can sustain, the horizontal asymptote of the logistic curve.
Logistic differential equation
dP/dt = kP(1-P/K), a growth rate that depends on both the current population and how close it is to capacity.
Inflection point
The point where a curve switches concavity, here occurring at P = K/2 on the logistic growth curve.
Growth rate (dP/dt)
The derivative of population with respect to time, measuring how fast the population is changing at a given instant.

Watch it explained

  1. How it worksHow does differentiating the logistic rate expose an inflection point at half the capacity?
  2. Worked exampleFind when a logistic population with capacity 1000, k = 0.2, and P(0) = 100 grows fastest.
  3. Common mistakeWhy doesn't the fastest growth happen when the population is at its largest?
  4. Ties togetherHow does the logistic inflection point connect to concavity from Unit 5?

Check yourself

Your turn1 of 2
Find the population at which a logistic population with carrying capacity 1545 grows fastest.

End of topic.