JentooChemistry

AP® Chemistry · Unit 6 · Topic 6.6

Enthalpy of Reaction

Enthalpy of reaction, delta H, is the heat released or absorbed per mole of reaction as written, so the heat you actually measure scales directly with how many moles react.

A thermochemical equation reports delta H for the reaction as written, tied to its coefficients. Burning one mole of methane, CH4(g) + 2O2(g) → CO2(g) + 2H_2O(l), releases 890 kJ. That number is fixed to one mole of CH4 reacting with two moles of O2. Burn two moles and you get twice the heat, because you are running the same reaction twice over. The energy change per mole never changes; only how many moles you run changes the total heat.

This is why delta H scales linearly with the coefficients. If you double every coefficient in the equation, delta H doubles too, because you have doubled the amount of reaction occurring. Multiply the whole equation by three, and delta H also multiplies by three, keeping the ratio of heat to moles constant. This scaling is what lets you convert between grams, moles, and kJ: convert mass to moles using molar mass, then multiply by delta H per mole to get total heat.

This idea sets up Hess's law, where you add thermochemical equations together and their delta H values add the same way, because each one still scales properly with its own moles. It also connects to calorimetry, where measured heat lets you work backward to find delta H per mole of a reaction actually run in a lab.

Key terms

enthalpy of reaction (delta H)
The heat released or absorbed when a reaction occurs in the molar amounts shown by its balanced equation.
thermochemical equation
A balanced chemical equation written together with its delta H value.
exothermic
A reaction that releases heat to the surroundings, giving delta H a negative value.
molar mass
The mass in grams of one mole of a substance, used to convert between grams and moles.

Watch it explained

  1. How it worksHow does delta H scale with the coefficients in a thermochemical equation?
  2. Worked exampleFind the heat released when 15.0 g of methane burns given a delta H of minus 890 kJ per mol.
  3. Common mistakeWhy isn't delta H reported per gram instead of per mole of reaction?
  4. Going furtherWhat happens to delta H when you multiply an entire thermochemical equation by three?

Check yourself

Your turn1 of 2
Methane combustion has delta H = -890 kJ/mol (methane molar mass 16.04 g/mol). Find the heat released, in kJ, when 56 g of methane burns.

End of topic.