JentooChemistry

AP® Chemistry · Unit 8 · Topic 8.8

Properties of Buffers

A buffer is a mix of a weak acid and its conjugate base that keeps pH nearly constant by having one partner absorb added acid and the other absorb added base.

A buffer holds two reservoirs at once: a weak acid (HA) and its conjugate base (A-), both present in significant amounts. Add strong acid, and the A- reservoir soaks up the extra H+, turning into HA. Add strong base, and the HA reservoir gives up a proton to neutralize it, turning into A-. Either way, the ratio of HA to A- shifts only a little, and since pH depends on the log of that ratio (Henderson-Hasselbalch: pH = pKa + log([A-]/[HA])), a small ratio shift means a small pH shift. Without both species present, there's nothing to catch the intruder.

Picture a flask with, say, 0.40 mol acetic acid and 0.40 mol acetate. Squirt in 0.05 mol NaOH: it reacts completely with 0.05 mol of the acetic acid, leaving 0.35 mol acetic acid and 0.45 mol acetate. The ratio barely moved from 1:1 to 0.78:1, so the pH barely moved from pKa. That's the whole mechanism: strong acid converts conjugate base into weak acid mole-for-mole, strong base does the reverse, and you plug the new amounts back into Henderson-Hasselbalch.

This is why HCl and NaCl never make a buffer: HCl ionizes completely, so there's no leftover molecular HA to react with added base, and Cl- is such a weak base it won't touch added acid. Blood uses the carbonic acid/bicarbonate pair (H_2CO3 / HCO3-) the same way: CO2 from exercising muscle forms H_2CO3, but bicarbonate absorbs the extra protons fast enough to hold pH near 7.4, linking this topic directly to the titration curves and equivalence points covered elsewhere in the unit.

Key terms

Buffer
A solution of a weak acid and its conjugate base that resists large pH changes when acid or base is added.
Conjugate base
The species left after a weak acid donates a proton, capable of accepting a proton back.
Henderson-Hasselbalch equation
pH = pKa + log([conjugate base]/[weak acid]), used to find a buffer's pH from the amounts of each species.
Mole-for-mole reaction
Added strong acid or base reacts completely and in equal moles with one buffer component, converting it into the other.

Watch it explained

  1. How it worksHow do the weak acid and its conjugate base take turns absorbing whatever gets added?
  2. How it worksDraw the particle picture of a buffer before and after a squirt of NaOH goes in.
  3. Common mistakeWhy isn't a mixture of a strong acid and its salt a buffer?
  4. Ties togetherHow does blood keep its pH near 7.4 while carbon dioxide pours into it during exercise?

Check yourself

Your turn1 of 2
A buffer contains 0.0848 mol of a weak acid and 0.0824 mol of its conjugate base (pKa = 5.36). After 0.0063 mol of strong acid is added (converting that much conjugate base into weak acid), find the new pH.

End of topic.