AP® Chemistry · Unit 5 · Topic 5.9
Pre-Equilibrium Approximation
When a mechanism's first step is a fast reversible equilibrium and the second step is slow, you use the equilibrium constant to rewrite the intermediate's concentration in terms of reactants, giving a rate law with only measurable species.
A rate law can only contain concentrations you can actually measure in a flask: starting reactants and sometimes products, never an intermediate that exists briefly mid-mechanism. That creates a puzzle when the slow step, the one that controls the overall rate, involves an intermediate. You need a way to trade that intermediate's concentration for something measurable. That's exactly what the pre-equilibrium approximation does.
It works when the first step of a mechanism is fast and reversible, reaching equilibrium before the slow second step has any real chance to drain it away. Because that first step sits at equilibrium, its forward and reverse rates are equal, so you can write K = [intermediate]/[reactants] and solve for the intermediate. Substitute that expression into the slow step's rate law, and the intermediate disappears, replaced by reactants raised to whatever powers the equilibrium expression demands. The result is an overall rate law built entirely from measurable starting materials, with an observed rate constant that is really a product like k2 times K.
This sits right next to the steady-state approximation, the other tool for erasing intermediates from a rate law. Pre-equilibrium assumes the first step is fast enough to stay balanced; steady-state instead assumes the intermediate's concentration stays roughly constant because it's used up as fast as it forms. Both roads lead to the same destination: a rate law written only in terms of things you can put a number to in the lab.
Key terms
- Intermediate
- A species formed in one mechanism step and consumed in another, never appearing in the overall reaction or final rate law.
- Pre-equilibrium approximation
- Treating a fast reversible first step as being at equilibrium to solve for an intermediate's concentration.
- Rate-determining step
- The slowest step in a mechanism, which controls the overall rate and whose rate law becomes the starting point for the overall one.
- Observed rate constant
- The experimentally measured constant in the overall rate law, often a combination like k2 times K from the mechanism.
Watch it explained
- How it worksHow does a fast reversible first step let you swap an intermediate out of the rate law?
- How it worksWalk me through deriving the rate law when step one is a fast equilibrium and step two is slow.
- Worked exampleFind the overall rate law for 2 NO plus O2 with a fast N2O2 pre-equilibrium and a slow second step.
- Common mistakeWhy isn't an intermediate allowed to stay in the final rate law expression?
Check yourself
End of topic.