JentooPhysics 1

AP® Physics 1: Algebra-Based · Unit 7 · Topic 7.4

Energy versus Position Curves

A spring's potential energy graphed against position is a parabola, U(x) = (1/2)kx2. A horizontal total-energy line crosses it at the turning points, and the gap between the line and the curve at any x is the kinetic energy there.

The potential energy stored in a spring is U(x) = (1/2)kx2. That's just a parabola opening upward, centered at x = 0, because U depends on x squared: stretch or compress the spring by the same amount in either direction and you store the same energy. The bottom of the parabola, at x = 0, is equilibrium, the natural length of the spring. Force is the negative slope of the potential energy curve, and the slope at the very bottom of a parabola is zero, so the force there is zero. That's exactly why equilibrium is a resting point: nothing pushes or pulls the mass when it sits at x = 0.

Total mechanical energy, kinetic plus potential, stays constant through the motion, so on this graph it's a flat horizontal line. Where that line crosses the parabola, all the energy is potential and none is kinetic, meaning the mass has stopped and is about to turn around. Those crossing points ARE the turning points, and the distance from x = 0 out to either one is the amplitude. At any position in between, kinetic energy is the vertical gap between the horizontal total-energy line and the parabola directly below it: KE = E_total - U(x). That gap is biggest at x = 0, where the mass moves fastest, and shrinks to zero right at the turning points.

Give the oscillator more energy and the horizontal line sits higher. A higher line hits the same parabola at points farther from the center, so the amplitude grows. This is the same energy-versus-position reasoning from the work and energy unit, just applied to a specific U(x) shape: the curve's bottom is stable equilibrium, the slope gives force everywhere, and the vertical gap below any horizontal energy line is always kinetic energy.

Key terms

Potential energy parabola
The graph of U(x) = (1/2)kx2 versus position, shaped like a bowl centered at equilibrium.
Total energy line
A horizontal line on the U(x) graph representing the constant sum of kinetic and potential energy.
Turning point
A position where the total-energy line meets the potential energy curve and kinetic energy is zero.
Amplitude
The maximum displacement from equilibrium, equal to the distance from x = 0 to a turning point.
Equilibrium position
The point where the potential energy curve has zero slope, so the restoring force is zero.

Watch it explained

  1. How it worksHow does a horizontal total-energy line cutting the parabola set the amplitude?
  2. How it worksWalk me through reading kinetic energy off the gap between the parabola and the total-energy line.
  3. Going furtherWhat happens to the whole picture when you give the oscillator more total energy?
  4. Ties togetherHow does this parabolic well connect to the potential energy curves from the work and energy unit?

Check yourself

Your turn1 of 2
On a graph of potential energy, a parabola, versus position for a spring oscillator, the total energy is drawn as a horizontal line. If the oscillator is given MORE total energy, a higher horizontal line, what happens to the amplitude of its motion?

End of topic.