JentooPhysics 2

AP® Physics 2: Algebra-Based · Unit 12 · Topic 12.2

Circular Motion in a Magnetic Field

A charged particle moving through a magnetic field feels a force always perpendicular to its velocity, so it never speeds up or slows down, only turns, tracing a perfect circle.

The magnetic force on a moving charge is F = qvB sin(theta), and its direction is always perpendicular to the velocity. A force perpendicular to velocity cannot change speed, since it does no work on the charge; it can only change direction. When the charge moves perpendicular to the field, the force stays perpendicular to v at every instant, constantly steering the particle without ever speeding it up. That steady sideways push is exactly what a centripetal force does: it bends a path into a circle instead of letting it fly straight.

Because the magnetic force is the centripetal force here, you can set them equal: qvB = mv2/r. Solve for r and you get r = mv/(qB). Everything you need, mass, charge, speed, field strength, plugs directly into this one equation. Notice the speed appears once in the numerator after cancellation, so faster particles sweep bigger circles, and stronger fields or larger charges pull the radius tighter.

If the particle's velocity has a component along the field direction, that component feels no force at all, since sin(theta) = 0 for motion parallel to B. That piece of the motion just coasts along at constant speed while the perpendicular piece keeps circling, and the two combine into a helix, a corkscrew path spiraling along the field line. This is the same centripetal reasoning from circular motion in mechanics, where gravity or tension or friction supplied F = mv2/r; here the magnetic force simply takes over that role.

Key terms

Centripetal force
The net force directed toward the center of a circular path, required to keep an object turning instead of moving straight.
Magnetic force on a charge
The force F = qvB sin(theta) exerted on a moving charge by a magnetic field, always perpendicular to the velocity.
Radius of circular path
r = mv/(qB), found by setting the magnetic force equal to the centripetal force.
Helical motion
A corkscrew path traced when a charged particle has velocity both along and perpendicular to the magnetic field.

Watch it explained

  1. How it worksHow does a force that is always perpendicular to velocity become a centripetal force?
  2. Worked exampleFind the radius of the path of an electron at 3.0 x 106 m/s in a 0.020 T field.
  3. Going furtherWhat changes about the path when the particle also has a velocity component along the field?
  4. Ties togetherHow does this circular motion connect to the centripetal force problems from mechanics?

Check yourself

Your turn1 of 2
Find the radius of the path of an electron at 7 x 106 m/s in a 0.0342 T field.

End of topic.