AP® Physics 2: Algebra-Based · Unit 13 · Topic 13.4
Diverging Lenses
A diverging lens is thinner in the middle than at the edges, so it spreads parallel rays apart instead of focusing them, always producing a virtual, upright, reduced image.
A diverging lens curves the opposite way from a magnifying lens: thin in the center, thicker at the edges. Parallel rays hitting it bend away from the center line instead of toward it, so they never meet on the far side. Trace them backward, though, and they all seem to come from one point on the same side as the object. That point is the focal point, but because the rays only appear to come from it, the focal length is written as negative, and the image is called virtual.
To locate the image, draw two of the three standard rays. One ray travels parallel to the axis, then bends as if coming from the near focal point. A second ray heads straight toward the far focal point but exits parallel to the axis. A third goes straight through the center of the lens, undeflected. All three, extended backward, cross at the same point on the object's side of the lens: that crossing is the virtual image, always upright and smaller than the object. The thin lens equation 1/f = 1/do + 1/di still works here, as long as f is negative.
This sits opposite the converging lens in the unit: converging lenses can make real or virtual images depending on object distance, but a diverging lens only ever makes one kind of image, no matter where the object sits. That single, predictable outcome is exactly why nearsighted corrective lenses are diverging: they shrink and spread the image so it focuses correctly in an eye that over-converges light.
Key terms
- Diverging lens
- A lens thinner at its center than at its edges, which spreads parallel light rays apart.
- Virtual image
- An image located where refracted rays only appear to originate, not where light actually converges.
- Focal length
- The distance from the lens to its focal point, taken as negative for diverging lenses.
- Thin lens equation
- The relation 1/f = 1/do + 1/di connecting object distance, image distance, and focal length.
Watch it explained
- How it worksHow does a lens that is thinner in the middle spread parallel rays apart instead of bringing them together?
- How it worksDraw the ray diagram for an object in front of a diverging lens and locate its virtual image.
- Worked exampleFind the image distance for an object 20 cm from a diverging lens of focal length -12 cm.
- Common mistakeWhy isn't a diverging lens capable of projecting an image onto a screen?
Check yourself
End of topic.