JentooPhysics 2

AP® Physics 2: Algebra-Based · Unit 10 · Topic 10.6

The Parallel-Plate Capacitor

A parallel-plate capacitor is two conducting plates separated by a gap that store equal and opposite charge, creating a uniform field between them. How much charge it holds per volt (its capacitance) depends only on the plate area and the gap width.

A camera flash needs a capacitor because a battery delivers energy slowly, through chemical reactions, while a flash needs a huge burst of current in a fraction of a second. The battery charges the capacitor up over a second or two, then the capacitor dumps all that stored charge almost instantly through the flash bulb. Batteries are good at slow, steady delivery. Capacitors are good at fast release.

Here is what happens as the capacitor charges: the battery pushes electrons onto one plate and pulls them off the other, so one plate becomes negative and the other positive, with equal magnitude charge +Q and -Q. Between the plates, a uniform electric field builds up, pointing from the positive plate to the negative plate. Charging stops when the voltage across the plates matches the battery's voltage. The capacitance C = Q/V tells you how much charge piles up per volt applied, and it depends only on the geometry of the capacitor, not on Q or V themselves. For parallel plates, C = epsilon0·A/d. Bigger plates (larger A) hold more charge for the same voltage, because there is more room for charge to spread out without crowding. A smaller gap (smaller d) also raises C, because the plates pull on each other's charge more strongly across a short distance, letting more charge accumulate before the voltage climbs.

This connects directly to the next idea: energy storage. Once you know C, you can find the energy parked in the field between the plates, which is exactly what a flash capacitor releases. It also sets up the separation experiment: changing geometry after charging reveals which quantities are fixed and which respond.

Key terms

Capacitance
The ratio C = Q/V, measuring how much charge a capacitor stores per volt across it.
Parallel-plate formula
C = epsilon0·A/d, where A is plate area and d is the gap between plates.
Permittivity of free space
epsilon0 = 8.85 x 10−12 F/m, a constant describing how easily an electric field forms in vacuum or air.
Isolated capacitor
A charged capacitor disconnected from any battery, so its total charge Q cannot change.

Watch it explained

  1. How it worksWalk me through what happens to the charge and field on two plates as a capacitor charges up.
  2. How it worksHow do plate area and gap width each change how much charge a capacitor can hold per volt?
  3. Worked exampleFind the capacitance of two 0.02 m2 plates separated by 1.0 mm of air.
  4. Going furtherWhat happens to the voltage across an isolated charged capacitor when you pull the plates apart?

Check yourself

Your turn1 of 2
Find the capacitance, in pF, of two 0.0379 m2 plates separated by 2.12 mm of air. Use epsilon0 = 8.85 x 10−12 F/m.

End of topic.