AP® Physics C: Electricity and Magnetism · Unit 8 · Topic 8.6

Gauss's Law with Cylindrical Symmetry

For charge distributions with cylindrical symmetry, a coaxial Gaussian cylinder makes the flux integral trivial, giving E = lambda/(2 π epsilon0 r) outside a line charge, a field that falls off as 1/r instead of 1/r2.

A point charge's field falls off as 1/r2 because its flux spreads over a sphere's surface area, which grows as r2. An infinite line of charge is different: the charge keeps going forever along the axis, so the field can only depend on distance from the wire, not position along it. Wrap a cylinder of radius r and length L around the wire, coaxial with it. The field points radially outward everywhere on the curved side, perpendicular to that surface, so flux there is just E times the side area, 2 π r L. On the two flat end caps, the field is parallel to the surface, so those contribute zero flux. Gauss's Law then reads E(2 π r L) = Q_enc/epsilon0, and since area grows only as r (not r2), the field thins out as 1/r.

The same trick handles a solid cylinder of uniform volume charge density rho. Outside the cylinder, all the charge is enclosed no matter how far out your Gaussian surface sits, so the field looks just like that of a line charge with lambda = rho times the cylinder's cross-sectional area. Inside, at radius r less than the cylinder's radius R, your Gaussian cylinder only encloses the charge within radius r, which scales as r2 (volume = π r2 L). Dividing that enclosed charge by the side area 2 π r L leaves one power of r, so the field grows linearly from the axis outward, then switches to 1/r falloff once you exit the cylinder.

This same reasoning extends naturally to a coaxial cable: between the inner conductor and outer shell, a Gaussian cylinder only encloses the inner conductor's charge, giving the familiar 1/r field, while outside the outer shell the enclosed charges cancel and the field vanishes.

Key terms

Cylindrical symmetry
A charge distribution whose field depends only on distance from a central axis, not on angle or position along that axis.
Gaussian cylinder
An imaginary coaxial cylindrical surface used to relate enclosed charge to flux via Gauss's Law.
Linear charge density (lambda)
Charge per unit length along a wire, measured in coulombs per meter.
Flux through end caps
Zero, because the radial field is parallel to the flat end surfaces and contributes no perpendicular component.

Watch it explained

  1. How it worksHow does a coaxial Gaussian cylinder make the two end caps contribute nothing to the flux?
  2. Worked exampleFind the field 3 cm from a long wire carrying 8 nC of charge per meter of length.
  3. Worked exampleFind the field inside and outside a long solid cylinder of uniform charge density rho.
  4. Going furtherWhat is the field in the gap between the inner and outer conductors of a coaxial cable?

Check yourself

Your turn1 of 2
Find the magnitude of the electric field 14 cm from a long straight wire carrying 20 nC of charge per meter of length. Use k = 8.99x109 N m2/C2.

End of topic.