AP® Physics C: Electricity and Magnetism · Unit 12 · Topic 12.2

The Magnetic Force on a Moving Charge

The magnetic force on a moving charge is F = qv x B: its size is qvB sin(theta), and it always points perpendicular to both the velocity and the field.

A magnetic field only pushes on charge that is already moving, and it never pushes along the direction of motion. That's what the cross product in F = qv x B is telling you: the force is perpendicular to both v and B at every instant. Because the force is always sideways to the velocity, it never has a component along the direction of travel, so it can change where the charge is headed but never how fast it's going.

To get the direction, point your right-hand fingers along v, then curl them toward B, and your thumb gives the direction of v x B. If the charge is negative, flip the result. Magnitude is F = qvB sin(theta), where theta is the angle between v and B; this is maximum when v and B are perpendicular (sin 90 = 1) and zero when v is parallel or antiparallel to B (sin 0 = 0), since there is no sideways direction left to push toward.

This force is the engine behind everything else in the unit: because it's always perpendicular to velocity, a charge moving perpendicular to a uniform field is pushed into circular motion, which is where the next topic on circular orbits in magnetic fields picks up. It also sets up the contrast with electric force, which can speed a charge up or slow it down because it acts along the field direction instead.

Key terms

Lorentz magnetic force
The force F = qv x B exerted by a magnetic field on a moving charge.
Right-hand rule
A method using the right hand to find the direction of v x B for a positive charge.
Cross product
A vector operation that produces a result perpendicular to both input vectors, with magnitude ab sin(theta).
Work by magnetic force
Always zero, since the force is perpendicular to velocity and so has no component along the displacement.

Watch it explained

  1. How it worksWalk me through using the right hand rule to get the direction of q v cross B.
  2. Worked exampleFind the force on a proton moving at 4 times 106 m/s across a 0.3 tesla field.
  3. Common mistakeWhy doesn't a magnetic field ever change the speed of a charged particle?
  4. Going furtherWhat happens to the force when the velocity lines up parallel with the field?

Check yourself

Your turn1 of 2
Find the magnitude of the magnetic force, in femtonewtons, on a proton moving at 7 x 106 m/s perpendicular to a 0.684 tesla magnetic field. Use e = 1.602x10−19 C.

End of topic.