AP® Precalculus · Unit 3 · Topic 3.9

Inverse Trig and Restricted Domains

Arcsin and arccos exist because sine and cosine repeat forever, so no inverse function can exist until you chop the domain down to one piece where each output happens exactly once.

Sine hits every value between -1 and 1 infinitely many times. sin(π/6) = 0.5, but so does sin(5pi/6), sin(13pi/6), and endlessly more. A function can only have an inverse if it's one-to-one, so before you can undo sine, you have to restrict it to a piece of its domain where it never repeats a y-value. The standard choice for sine is the interval from -π/2 to π/2: on that stretch sine climbs steadily from -1 to 1, hitting each value exactly once. Restricted to that domain, sine is invertible, and its inverse is arcsin(x), sometimes written sin−1(x).

Because arcsin is the inverse of this restricted sine, its graph is the reflection of that piece of the sine curve over the line y = x. Restricted sine runs from (-π/2, -1) to (π/2, 1); arcsin runs from (-1, -π/2) to (1, π/2), swapping x and y coordinates the way every inverse does. Feed arcsin a ratio between -1 and 1, and it hands back the one angle in [-π/2, π/2] with that sine value. Cosine needs the same treatment but a different window, since cosine isn't one-to-one on [-π/2, π/2] either (cos(-π/4) = cos(π/4)). Cosine is restricted to [0, π] instead, where it steadily falls from 1 to -1 without repeating, and arccos is built from that piece.

This restrict-then-reflect pattern is exactly how all the inverse trig functions get built, including arctan later with its own restricted interval. It also explains why arcsin and arccos only ever output angles from a limited range: they're built to return one answer, not all the infinitely many true ones.

Key terms

Inverse function
A function that reverses another function, swapping its inputs and outputs, and exists only where the original is one-to-one.
Restricted domain
A deliberately shrunk input interval chosen so a repeating function becomes one-to-one and invertible.
arcsin(x)
The inverse of sine restricted to [-π/2, π/2]; returns the unique angle in that interval with the given sine value.
arccos(x)
The inverse of cosine restricted to [0, π]; returns the unique angle in that interval with the given cosine value.
One-to-one
A function where every output comes from exactly one input, a requirement for an inverse to exist.

Watch it explained

  1. How it worksHow does chopping sine down to the interval from -π/2 to π/2 make it invertible?
  2. Worked exampleGraph y = arcsin(x) as the reflection of the restricted sine curve over the line y = x.
  3. Common mistakeWhy isn't arcsin(x) the same as one divided by sin(x)?
  4. Going furtherWhat restricted piece does arccosine use, and why is it a different interval?

Check yourself

Your turn1 of 2
Find arcsin(0.35) in radians (a decimal answer).

End of topic.