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SAT® · Math: Advanced Math

Solving a Quadratic in Standard Form by Factoring

To solve a quadratic by factoring, move every term to one side so the equation equals zero, factor the expression into two binomials, then set each binomial equal to zero.

Factoring only works against zero. The zero product rule says that if two things multiply to give zero, at least one of them has to be zero — there's no equivalent rule for a product equaling 28 or 5 or any other number. That's why the first move, always, is herding every term onto one side so the equation reads ax2 + bx + c = 0. Skip this step and even a perfectly factored expression tells you nothing about the solutions.

Once the equation equals zero, factor the quadratic into two binomials, (x - p)(x - q) = 0. Each binomial becomes its own mini-equation: x - p = 0 and x - q = 0, giving solutions x = p and x = q. This connects directly to the graph: p and q are the x-intercepts of the parabola y = ax2 + bx + c, the points where the curve crosses the x-axis. It also runs in reverse — if you're told the zeros of a quadratic, you can rebuild the factored form and expand it back to standard form.

This skill sits right next to the quadratic formula and completing the square as the three standard ways to solve ax2 + bx + c = 0. Factoring is fastest when the numbers cooperate; when they don't, the quadratic formula always works. Recognizing which tool fits a given equation — and never dividing by a variable to 'simplify' — is what separates a clean solve from a lost solution.

Key terms

Standard form
A quadratic written as ax2 + bx + c = 0, with everything on one side and zero on the other.
Zero product rule
If two factors multiply to zero, at least one of the factors must itself equal zero.
Binomial factor
A two-term expression like (x - p) that, when multiplied by another binomial, reproduces the quadratic.
Zero (of a function)
A value of x where the function equals zero, matching an x-intercept on its graph.

Watch it explained

  1. How it worksHow do you travel from ax2+bx+c=0 to two binomials and then to two answers?
  2. Worked exampleSolve x2+3x=28 by moving every term to one side and factoring what is left.
  3. Common mistakeWhy doesn't dividing both sides of x2=5x by x count as solving the equation?
  4. Worked exampleSolve 3x2-14x+8=0 by factoring, then find the sum of the two solutions.

Check yourself

Your turnmedium1 of 3
Solve x2 + 7x = 20. What is the greater solution? Round to the nearest hundredth if necessary.

End of topic.