AP® Statistics · Unit 5 · Topic 5.3

Reading a Regression Equation

A regression equation y-hat = a + bx lets you predict a y-value for any x by plugging in, where b is the slope (change in y per unit x) and a is the y-intercept (predicted y when x = 0).

A least-squares regression line is just an equation, y-hat = a + bx, and it works like any line you've plugged numbers into before. The hat on y is a reminder: this is a predicted value, not an observed one. You get it by taking an x-value, multiplying by the slope b, and adding the intercept a. That's the whole mechanism — the statistics is in how a and b got chosen, but reading the line is pure arithmetic.

The slope b tells you how y changes, on average, for every one-unit increase in x. Always state it in context and in the original units: 'for every additional hour studied, predicted score increases by 1.7 points,' not just '1.7.' The intercept a is the predicted y when x = 0. Sometimes that's a real, sensible value — other times x = 0 is nonsense in context, like a height of zero, and then the intercept is just a mathematical anchor for the line, not a claim about the world.

This reading skill is what makes the rest of the unit matter: once you can state slope and intercept in words, you can check whether a prediction is trustworthy. Predicting inside the range of your x-data, called interpolation, is reasonable. Predicting far outside it, extrapolation, is risky, because you're assuming the same straight-line pattern keeps going where you have no evidence it does. That risk is exactly why the next ideas — residuals and checking linearity — matter before you trust any prediction.

Key terms

y-hat
The predicted value of y produced by the regression equation, as opposed to an actually observed y.
slope (b)
The predicted change in y for every one-unit increase in x.
intercept (a)
The predicted value of y when x equals 0, meaningful only if x = 0 is realistic.
interpolation
Predicting a y-value for an x inside the range of the observed data.
extrapolation
Predicting a y-value for an x far outside the observed data's range, which is unreliable.

Watch it explained

  1. How it worksHow do the slope and the intercept of a regression line each get read in context?
  2. Worked exampleFind the predicted value at x = 12 for the line y-hat = 3.4 + 1.7x.
  3. Common mistakeWhy isn't the intercept always meaningful in a real regression?
  4. Going furtherWhat happens to a prediction when x sits far outside the range of the data?

Check yourself

Your turn1 of 2
Find the predicted value at x = 19 for the line y-hat = 7 + 2.77x.

End of topic.