AP® Calculus AB · Unit 4 · Topic 4.4

Introduction to Related Rates

Related rates problems link two or more quantities that change over time by differentiating an equation connecting them with respect to time, then plugging in numbers only at the end.

Picture filling a cone-shaped cup at a steady rate. Near the bottom, the cone is narrow, so a little water raises the level a lot. Near the top, the cone is wide, so the same amount of water barely moves the level. Volume and height are tied together by the cone's geometry, and that relationship bends, so a constant rate of change in volume does not mean a constant rate of change in height. Related rates problems capture exactly this: quantities connected by an equation change at different, often non-constant, rates.

The method is implicit differentiation with a twist: every variable is understood to be a function of time t, even when t does not appear in the equation itself. You differentiate both sides with respect to t, applying the chain rule to each variable, which introduces its rate of change, like dr/dt or dV/dt. For an equation with two variables changing at once, like area depending on both length and width, you also need the product rule, since each variable's rate contributes separately to the total rate of change. Only after differentiating do you substitute the specific numbers given for that instant.

This topic sits right after linear approximation and local linearity, reusing the same chain-rule machinery but now applied to time rather than x. It also sets up the rest of unit four's applications, where derivatives carry units and meaning, such as velocity and acceleration, reinforcing that a derivative is a rate, not just a slope on a graph.

Key terms

related rates
Problems finding how one changing quantity's rate relates to another's through an equation connecting them.
implicit differentiation
Differentiating both sides of an equation with respect to a variable without first solving for one variable.
chain rule
The rule that differentiates a composed function by multiplying the derivative of the outer function by the derivative of the inner one.
rate of change
How fast a quantity changes with respect to time, written as a derivative like dV/dt.

Watch it explained

  1. How it worksHow does differentiating an equation with respect to time link two changing quantities?
  2. Worked exampleFind dA/dt for a circle whose radius grows at 2 cm per second when the radius is 5 cm.
  3. Common mistakeWhy isn't it safe to plug the given numbers in before you differentiate?
  4. Going furtherWhat changes when a second quantity in the equation is varying with time too?
  5. Ties togetherHow does differentiating both sides with respect to time reuse implicit differentiation?

Check yourself

Your turn1 of 3
A circle's radius is growing at 4.33 cm per second. Write dA/dt as a function of r (before plugging in a specific radius).

End of topic.