AP® Calculus AB · Unit 4 · Topic 4.5

Solving Related Rates Problems

Related rates problems link two or more quantities that change over time through an equation, then use implicit differentiation to find how their rates of change relate at a specific instant.

Every related rates problem hides a geometric or physical relationship that stays true at every moment, even though the pieces inside it are moving. Your job is to find that equation first: a Pythagorean relationship for a ladder, a volume formula for a filling tank, similar triangles for a shadow. Once you have an equation connecting the variables, differentiate both sides with respect to time using the chain rule. Every variable that changes with time gets its own dt term, even ones that aren't the one you're solving for. That step turns a static geometric fact into a sentence about rates.

After differentiating, plug in the specific numbers given at the instant you care about, then solve for the unknown rate. Order matters here: differentiate first, substitute second. If you plug numbers in before differentiating, you lose the variable and the derivative becomes zero. This is also why the ladder's top doesn't slide down at a constant speed even though the base moves at a constant speed: the differentiated equation shows the unknown rate depends on the current position, not just on the other rate.

This topic is where derivatives stop being abstract slopes and start being physical speeds with units attached, connecting directly to the motion problems earlier in the unit. It also sets up linear approximation, which asks what happens over a small time step once you know a rate at an instant.

Key terms

related rates
A problem type where two or more quantities change with time and are linked by an equation, so their rates of change are also linked.
implicit differentiation
Differentiating both sides of an equation with respect to time, applying the chain rule to every variable that depends on time.
dy/dt
The rate of change of a quantity y with respect to time, often the unknown you solve for last.
similar triangles
A geometric tool used in cone and shadow problems to relate two changing lengths through a fixed ratio.

Watch it explained

  1. How it worksHow do you pick the equation that ties two rates together before you differentiate?
  2. Worked exampleFind how fast the top of a 13 ft ladder drops when the base is 5 ft out moving at 2 ft per second.
  3. Worked exampleFind how fast the water rises in a cone of radius 4 and height 8 filling at 6 cubic ft per minute.
  4. Common mistakeWhy isn't the ladder top's rate constant when the base moves at a constant rate?

Check yourself

Your turn1 of 3
A 18 ft ladder leans against a wall. The base is being pulled away from the wall at 2.77 ft/s. Write the speed at which the top of the ladder slides down the wall as a function of x, the base's distance from the wall.

End of topic.