AP® Calculus BC · Unit 9 · Topic 9.7

Defining Polar Coordinates and Differentiating in Polar Form

Polar coordinates locate a point by distance r from the origin and angle theta from the positive x-axis, instead of by x and y. To find slope on a polar curve, convert r(theta) into x(theta) and y(theta), then compute dy/dx as (dy/dtheta)/(dx/dtheta).

A point in polar coordinates is given by r, how far from the origin, and theta, what angle that distance makes with the positive x-axis. Some shapes that look messy as y = f(x) become clean in polar form. A circle centered at the origin is just r = constant. A flower-shaped curve or a heart-shaped limacon, awkward in x and y, often collapses into a short equation like r = 2 + 2cos(theta). Labeling points by direction and distance matches how these curves actually grow, so the algebra shrinks.

The link between the two systems never changes: x = r cos(theta) and y = r sin(theta). Going backward, r = √(x2+y2) and tan(theta) = y/x. Because r itself is usually a function of theta in these curves, x and y both become functions of theta too: x(theta) = r(theta)cos(theta), y(theta) = r(theta)sin(theta). That turns a polar curve into a parametric one, and slope follows the same rule as any parametric curve: dy/dx = (dy/dtheta)/(dx/dtheta), found by differentiating x(theta) and y(theta) with the product rule and dividing.

This topic is the bridge into polar calculus: once you can write dy/dx, the next topics ask you to find horizontal and vertical tangents, then move to arc length and the area swept out by r as theta sweeps through an interval. Everything downstream depends on comfortably switching between r, theta, x, and y, and on trusting the quotient dy/dtheta over dx/dtheta instead of reaching for a polar-specific slope formula.

Key terms

Polar coordinates
A way to locate a point using distance r from the origin and angle theta from the positive x-axis.
Pole
The fixed origin point from which r is measured in a polar coordinate system.
Conversion equations
The relations x = r cos(theta) and y = r sin(theta) linking polar and rectangular coordinates.
dy/dx in polar form
The slope of a polar curve, computed as (dy/dtheta) divided by (dx/dtheta) after writing x and y as functions of theta.

Watch it explained

  1. How it worksHow do r and theta convert into x and y, and then back again?
  2. Worked exampleFind dy/dx for the polar curve r = 2 + 2cos(theta) at theta = π/2.
  3. Worked exampleFind dy/dx for the polar curve r = 3 - 3sin(theta) at theta = π.

Check yourself

Your turn1 of 2
Find dy/dx for the polar curve r = 4 + 4cos(theta), as a function of theta.

End of topic.