AP® Calculus BC · Unit 9 · Topic 9.2
Second Derivatives of Parametric Equations
For parametric curves, d2y/dx2 means differentiate dy/dx with respect to t, then divide that result by dx/dt again — not a simple ratio of raw second derivatives.
With x and y both written in terms of t, dy/dx is already a quotient: (dy/dt) divided by (dx/dt). That quotient is a function of t, not of x, so to find its derivative with respect to x you can't just differentiate it in t and stop. You need d/dx, and the chain rule says d/dx of anything equals its d/dt divided by dx/dt. So the second derivative needs that same division applied a second time.
Mechanically: first find dy/dx as a function of t. Then differentiate that whole expression with respect to t, getting d/dt[dy/dx]. Finally divide by dx/dt one more time. The result, d2y/dx2, is still a function of the parameter t, not of x directly — you read off concavity at a given t-value rather than an x-value. This matters because the curve's shape near a point is only partly described by its slope; the second derivative tells you whether the curve bends upward or downward in y as x increases, which is exactly the role concavity plays for ordinary functions.
This topic sits right after finding dy/dx parametrically, and it feeds directly into analyzing motion: if x and y describe position, the same ideas becomes tools for reading acceleration and curvature, and later for sketching parametric and polar curves accurately. Mastering the two-step division here is what makes those later applications reliable.
Key terms
- Parametric equations
- A pair of equations giving x and y separately in terms of a third variable t.
- dy/dx (parametric)
- The slope of the curve, found as (dy/dt) divided by (dx/dt).
- d2y/dx2
- The second derivative, found by differentiating dy/dx with respect to t and dividing that result by dx/dt.
- Concavity
- Whether a curve bends upward (positive second derivative) or downward (negative) as x increases.
Watch it explained
- How it worksHow do I differentiate dy/dx with respect to t and then convert it back to x?
- Worked exampleFind the second derivative d2y/dx2 for x = t2 and y = t3 at t = 1.
- Common mistakeWhy isn't the parametric second derivative just d2y/dt2 divided by d2x/dt2?
- Going furtherWhat does the sign of a parametric second derivative say about concavity?
Check yourself
End of topic.