AP® Calculus BC · Unit 4 · Topic 4.4
Introduction to Related Rates
Related rates problems link two quantities tied together by an equation, then use differentiation with respect to time to turn a known rate of change into an unknown one.
When two quantities are connected by an equation, they're forced to change together. A circle's area depends on its radius, so if the radius grows, the area must grow too, and the equation A = π r2 controls exactly how fast. The job of related rates is to turn that controlling equation into a statement about speeds: how fast one thing changes compared to how fast the other does.
The move is to differentiate the whole equation with respect to time, treating every quantity as a function of t, even if t never appears explicitly. Differentiating A = π r2 with respect to time uses the chain rule, since r itself is changing: dA/dt = 2 π r (dr/dt). This single line now connects the two rates, dA/dt and dr/dt, through the current value of r. Plug in r = 3 and dr/dt = 2, and dA/dt = 2 π (3)(2) = 12 π square cm per second. The radius has to stay a variable through the differentiation step; it only becomes a number afterward, once the derivative has captured how A responds to changes in r.
This same pattern, write an equation linking two quantities, differentiate with respect to time, substitute known values last, is the entire toolkit for every related rates problem that follows. A ladder sliding down a wall uses the Pythagorean theorem instead of a circle's area formula, and a draining cone uses the volume of a cone, but the mechanism never changes. Mastering this simple circle case is really mastering the whole method.
Key terms
- Related rates
- A problem type where the rates of change of two or more linked quantities are connected through a shared equation.
- Implicit differentiation with respect to time
- Differentiating both sides of an equation using the chain rule, treating each quantity as a function of time.
- dr/dt
- The rate at which the radius changes over time, often given as a known quantity in the problem.
- dA/dt
- The rate at which the area changes over time, usually the unknown quantity being solved for.
Watch it explained
- How it worksHow does differentiating an equation with respect to time connect two different speeds?
- Worked exampleFind how fast a circle's area grows when its radius is 3 cm and growing at 2 cm per second.
- Common mistakeWhy doesn't plugging in the radius before differentiating give the right answer?
- Ties togetherHow does differentiating this single equation with respect to time set up the ladder and cone problems worked out next?
Check yourself
End of topic.