AP® Calculus BC · Unit 4 · Topic 4.5

Solving Related Rates Problems

Related rates problems link two changing quantities through an equation, then use derivatives with respect to time to find how fast one changes given the other's rate.

Every related rates problem hides a static equation connecting two or more quantities, like x2+y2=L2 for a sliding ladder. The quantities change over time, so you differentiate the whole equation with respect to time t, using the chain rule on each variable. That turns x and y into dx/dt and dy/dt, linking the rates the same way the original equation linked the quantities. The algebra never changes; only the geometry does.

The setup does the real work. Draw the picture, label every quantity that changes, and write the one equation that is always true, not just true at the instant you care about. Plug in the known rate and the known value of the variable at that instant only after differentiating, never before. This is why the ladder's top accelerates without limit as the base approaches the wall: dy/dt depends on x and y, and as y shrinks toward zero while x stays positive, dy/dt blows up, even though dx/dt stays constant. The base moves at a steady rate; the top's rate is a function of position, not a constant.

Related rates sits right after implicit differentiation for a reason: every setup here is an implicit differentiation problem wearing a word problem's clothes. It also previews optimization in the next unit, where instead of rates you'll track changing quantities to find a maximum or minimum, using the same habit of writing one clean equation before touching a derivative.

Key terms

Related rates
Problems that find the rate of change of one quantity using its relationship to another quantity's known rate.
Implicit differentiation
Differentiating both sides of an equation with respect to time without first solving for one variable.
Chain rule
The rule that lets you differentiate a quantity like x2 with respect to time as 2x(dx/dt).
Similar triangles
Triangles with proportional sides, often used to relate two changing lengths, like radius and height in a draining cone.

Watch it explained

  1. How it worksHow do I set up a related rates problem so the picture does most of the work?
  2. Worked exampleFind how fast the top of a 10 ft ladder slides down when the base is 6 ft out moving at 2 ft per second.
  3. Worked exampleFind how fast the water level rises in a cone at depth 4 m when water pours in at 3 cubic meters per minute.
  4. Worked exampleFind how fast a shadow lengthens when a 6 ft person walks from a 15 ft lamppost at 4 ft per second.
  5. Common mistakeWhy isn't the speed of the shadow's tip the same as the speed the shadow lengthens?

Check yourself

Your turn1 of 2
A 13 ft ladder leans against a wall, its base sliding away at 2 ft per second. Write the speed at which the top slides down the wall as a function of x, the base's distance from the wall.

End of topic.