AP® Calculus BC · Unit 10 · Topic 10.6

The Limit Comparison Test

The Limit Comparison Test says two series with positive terms share the same fate — both converge or both diverge — if the ratio of their terms settles on a positive finite number as n grows.

When two series have terms that behave the same way for large n, they should converge or diverge together, even if one is always a little bigger or smaller than the other term by term. The direct comparison test needs a clean inequality for every n, which is often messy to prove or just false near the start. Limit comparison sidesteps that: instead of comparing term sizes directly, you compare their long-run behavior by taking the limit of an over bn as n goes to infinity.

If lim (an / bn) = L, where L is a positive finite number, the two series are tied together — an behaves like a constant multiple of bn for large n, so whatever bn's series does, an's series does too. You pick bn to be a simpler series, usually a p-series like 1/n or 1/n2, whose convergence you already know. Find the limit of the ratio, check that it is positive and finite, then read off the same conclusion for your original series. If the limit is 0 or infinite, the test gives no conclusion, and you need another method.

This test matters most when the series looks almost like a p-series but has extra terms cluttering the numerator or denominator, the kind of thing that makes direct comparison inequalities painful. It sits alongside the direct comparison test and the integral test as tools for series with positive terms, and it leans on your fluency with p-series and the harmonic series as the known benchmarks everything else gets measured against.

Key terms

Limit Comparison Test
A test stating that series with positive terms share convergence behavior if the limit of their term ratio is a positive finite number.
p-series
A series of the form sum of 1/np, which converges if p > 1 and diverges if p ≤ 1.
Direct Comparison Test
A test that concludes convergence or divergence from a term-by-term inequality between two series, valid for all n.
Harmonic series
The series sum of 1/n, the p = 1 case of a p-series, which diverges.

Watch it explained

  1. How it worksHow does taking a limit of an over bn rescue a comparison the raw inequality blocks?
  2. Worked exampleShow me that the sum of (2n + 1)/(n3 + 4) converges using limit comparison with 1/n2.
  3. Worked exampleFind what limit comparison with 1/n says about the sum of 1/(3n - 2).

Check yourself

Your turn1 of 2
Using limit comparison with 1/n2, what does the limit comparison test conclude about the sum of (4n + 4)/(n3 + 8)?

End of topic.