AP® Calculus BC · Unit 10 · Topic 10.3

The nth Term Test for Divergence

If the terms of a series don't shrink to zero, the series cannot converge. The nth Term Test checks the limit of an: a nonzero or nonexistent limit proves divergence, but a limit of zero proves nothing.

A sum of infinitely many numbers can only settle to a finite value if the pieces you're adding eventually become negligible. If an does not approach 0, then every term you add keeps contributing a real amount, so the running total either grows without bound or oscillates forever. That's the whole idea behind the nth Term Test for Divergence: compute lim(n→infinity) an. If that limit is nonzero, or doesn't exist, the series sum(an) diverges. No further work needed.

Here's the catch: this test only ever proves divergence. If lim an = 0, you've learned nothing about convergence yet, because terms shrinking to zero is necessary but not sufficient. The harmonic series sum(1/n) is the classic warning: 1/n → 0, yet the partial sums grow without bound and the series diverges anyway. So a zero limit just means 'try another test' — ratio, integral, comparison, whatever fits the series' shape.

This test is usually your first move on any series, because it's fast: find the limit, and if it's not 0, you're done. It sits right before the more delicate tools later in the unit that handle the zero-limit case, like the integral test, comparison tests, and the ratio test, which actually measure how fast the terms shrink rather than just whether they shrink at all.

Key terms

nth term test for divergence
If lim(n→infinity) an is nonzero or does not exist, the series sum(an) diverges.
necessary but not sufficient
A condition that must be true for convergence but whose truth alone does not guarantee convergence.
harmonic series
The series sum(1/n), whose terms shrink to 0 but whose partial sums still grow without bound, so it diverges.
partial sum
The sum of the first n terms of a series, used to decide whether the total settles toward a finite value.

Watch it explained

  1. How it worksHow does the limit of the terms give a one-way test that can only ever prove divergence?
  2. Worked exampleShow me why the series with terms n/(2n + 3) has to diverge.
  3. Worked exampleShow me why the series with terms (-1)n never converges by the nth term test.
  4. Common mistakeWhy doesn't terms going to zero prove that a series converges?

Check yourself

Your turn1 of 2
Find the limit of the terms 7n/(6n + 8) as n approaches infinity (used to show this series diverges by the nth term test).

End of topic.