AP® Physics C: Mechanics · Unit 6 · Topic 6.3

Angular Momentum of a Particle Moving in a Straight Line

A particle moving in a straight line has angular momentum about any point not on that line, equal to its momentum times the perpendicular distance from the point to the line. Nothing has to curve for angular momentum to exist.

Angular momentum about a point, L = r x p, only cares about one thing beyond mass and speed: how far off-axis the motion is. Write it as L = m v r_perp, where r_perp is the perpendicular distance from your chosen reference point to the line the object is traveling along, extended infinitely in both directions. That distance never changes as the particle moves, even though r itself (the vector from the point to the particle) is constantly changing length and direction. That is why a particle sailing past you in a perfectly straight line has constant angular momentum about you the whole time, from far away, to closest approach, to far away again.

The mechanism is the cross product itself. r x p = r p sin(theta), and r sin(theta) is exactly the perpendicular distance from the reference point to the line of motion. As the particle approaches, r shrinks but theta grows toward 90 degrees, and the product r sin(theta) stays fixed at r_perp. Only at the instant of closest approach does r itself equal r_perp, with velocity exactly perpendicular to r.

This idea is what makes angular momentum conservation work for orbits and scattering problems later in the unit. A planet or comet moving under gravity would travel in a straight line if the force vanished, and it carries angular momentum about the sun throughout, which is exactly why that angular momentum stays constant as gravity bends the path into a curve. Seeing straight-line angular momentum first makes the conservation law in orbital motion feel inevitable rather than mysterious.

Key terms

Angular momentum
The rotational analog of momentum, L = r x p, measured about a chosen reference point.
Perpendicular distance (r_perp)
The shortest distance from the reference point to the infinite line along which the particle travels.
Cross product
A vector operation giving r x p magnitude r p sin(theta), where theta is the angle between r and p.
Closest approach
The point along a straight path where the particle's distance to the reference point equals r_perp and velocity is perpendicular to r.

Watch it explained

  1. How it worksHow does r crossed with p depend on the perpendicular distance to your reference point?
  2. Worked exampleFind the angular momentum about the origin of a 2 kg mass at (0, 3) m moving at 4i m/s.
  3. Common mistakeWhy doesn't angular momentum require anything to actually be going around in a circle?
  4. Going furtherWhat happens to that angular momentum as the object sails past its closest approach?

Check yourself

Your turn1 of 2
Find the angular momentum about the origin of a 6 kg mass at (0, 6) m moving at 9i m/s.

End of topic.