AP® Physics C: Mechanics · Unit 6 · Topic 6.2

The Rotational Work-Energy Theorem

The rotational work-energy theorem says net work done by torques equals the change in a wheel's rotational kinetic energy, 1/2 I omega2. Work in, spin speed out.

A free wheel with a fixed axis can't move its center of mass, so it can't store energy as translational kinetic energy. Any work a motor does on it has nowhere else to go, it all becomes rotational kinetic energy. That's the rotational twin of the work-energy theorem you already know for sliding blocks, just swap force for torque, distance for angle, mass for moment of inertia, and linear speed for angular speed.

The mechanism mirrors the linear case exactly. Net work equals force times distance in a straight line problem; here net rotational work equals torque times angular displacement, W = tau times theta, for a constant torque. That work changes rotational kinetic energy: W_net = (1/2) I omegaf2 - (1/2) I omegai2. Because I plays the role mass played before, a large I needs more work to reach the same omega, just like a heavy object needs more work to reach the same speed. The theorem works for varying torque too, as long as you use the correct general definition of work as the integral of tau d(theta).

This theorem connects directly to power and to angular momentum, the next ideas in this unit. Rotational power is P = tau times omega, the exact analog of P = F dot v, and it tells you the rate work is being delivered to a spinning object. Where this topic cares about energy, the next one cares about angular momentum, L = I omega, which is conserved when net external torque is zero, even while kinetic energy might change. Keeping these two conserved quantities separate, energy from work and angular momentum from torque impulse, is what the rest of the unit builds on.

Key terms

Rotational kinetic energy
The energy of spinning motion, equal to one half I omega squared.
Moment of inertia (I)
A rigid body's resistance to changes in rotational motion, depending on mass distribution about the axis.
Net rotational work
The total work done by all torques acting on a rotating object, equal to torque times angular displacement for constant torque.
Angular displacement (theta)
The angle, in radians, through which an object has rotated.
Rotational power
The rate of doing rotational work, equal to torque times angular velocity, P = tau omega.

Watch it explained

  1. How it worksHow does net rotational work equal the change in one half I omega squared?
  2. Worked exampleFind the final angular speed of a wheel with I = 0.6 kg m2 given 90 J of work from rest.
  3. Worked exampleFind how many turns a 5 N m friction torque needs to stop a wheel at 30 rad/s with I = 0.3 kg m2.
  4. Ties togetherHow does rotational power compare with the linear form, force dotted into velocity?

Check yourself

Your turn1 of 2
Find the final angular speed of a wheel with I = 1.33 kg m2, starting from rest, given 111 J of work.

End of topic.