AP® Physics C: Mechanics · Unit 3 · Topic 3.5
Instantaneous Power
Instantaneous power is the rate at which force does work at a single moment, given by P = F dot v. It tells you how hard an engine is working right now, not over a whole trip.
Work is force acting along a path, and power is just how fast that work gets done. Start from W as the integral of F dot dr, and take the time derivative: dW/dt = F dot (dr/dt) = F dot v. That's instantaneous power. When force and velocity point the same way, the dot product collapses to a plain product, P = Fv. This is why a car's engine strains hardest at highway speed rather than at a stoplight: the driving force needed to fight resistance barely changes, but velocity has climbed, so the product Fv, the power demand, climbs with it.
This single equation also explains top speed. A real engine has a maximum power output it can sustain, not a maximum force. As a car speeds up, resistive forces (drag, friction) stay roughly fixed or grow, but the velocity needed to turn a given force into the engine's full power output keeps rising. Top speed is reached when all available power is spent just cancelling resistance at constant velocity: P = f v, with zero leftover power to accelerate. Solve for v and you have the ceiling.
Power connects directly to the energy accounting of this unit. If you know P(t), integrating it over time hands you back total work done, W = integral of P dt, which is just the area under a power versus time graph. That's the same work that feeds into the work-energy theorem and potential energy bookkeeping covered elsewhere in this unit: force tells you what's pushing, power tells you how fast energy is changing hands, and work tells you the total transferred.
Key terms
- Instantaneous power
- The rate at which work is being done at a specific moment, P = dW/dt.
- P = F dot v
- Power as the dot product of the force vector and the velocity vector at an instant.
- Top speed
- The constant velocity reached when all of an engine's power output is used just to balance resistive force.
- Area under a power-time graph
- The integral of power over time, which equals the total work done.
Watch it explained
- How it worksHow does P equal to force dotted with velocity fall straight out of dW/dt?
- Worked exampleFind the instantaneous power delivered by a 300 N driving force to a car moving at 28 m/s.
- Worked exampleFind the top speed of a 150 kW car that faces a total resistive force of 900 N.
- Ties togetherHow does the area under a power versus time graph get you back to the total work?
Check yourself
End of topic.