AP® Physics C: Mechanics · Unit 3 · Topic 3.1

The Work-Energy Theorem

The work-energy theorem says the net work done on an object equals its change in kinetic energy: W_net = delta KE = one half m vf2 minus one half m vi2.

Force changes motion over time, but work changes motion over distance, and the two are connected through speed. If you push something and keep pushing as it moves, you are feeding energy into its motion, and that energy shows up entirely as a change in one half m v2. That is the whole theorem: add up every bit of force along every bit of path, and the total is exactly how much kinetic energy was gained or lost. No separate bookkeeping for different forces is needed if you only care about the start and end speeds.

The mechanism comes straight from Newton's second law. Start with F = m dv/dt, then write work as the integral of F dx. Swap dx for v dt, and dv/dt times v dt becomes v dv. Integrating m v dv from the initial to final speed gives one half m vf2 minus one half m vi2. So the net work integral is not a coincidence matching kinetic energy, it IS kinetic energy's antiderivative, built from the same acceleration that defines force in the first place.

This theorem is the scalar cousin of the vector equations from Unit 2: it throws away direction and time, keeping only speed and distance, which is why it collapses problems that would be painful with kinematics alone. It also sets up potential energy, the next idea in this unit, since work done against a conservative force gets stored rather than lost, and the two together give the full energy accounting that makes multi-force, multi-stage problems solvable without re-deriving motion at every step.

Key terms

Work-energy theorem
The statement that the net work done on an object equals its change in kinetic energy.
Kinetic energy
The energy of motion, equal to one half m v2 for an object of mass m moving at speed v.
Net work
The total work done by all forces acting on an object, found by summing or integrating force along the path.
Conservative force
A force whose work depends only on start and end position, not the path taken, allowing a potential energy to be defined.

Watch it explained

  1. How it worksHow does integrating F = m dv/dt over distance produce the change in one half m v squared?
  2. Worked exampleFind the speed of a 3 kg block that starts at rest and has 24 J of net work done on it.
  3. Worked exampleFind the stopping distance of a 1000 kg car at 20 m/s braked by a steady 5000 N force.
  4. Common mistakeWhy doesn't a force perpendicular to the motion change an object's kinetic energy at all?

Check yourself

Your turn1 of 2
Find the speed of a 7 kg block that starts at rest and has 42 J of net work done on it.

End of topic.