AP® Physics C: Mechanics · Unit 7 · Topic 7.5
The Physical Pendulum
A physical pendulum is any rigid body that swings about a pivot under gravity; its period depends on its full moment of inertia about the pivot, not just the distance to its center of mass, giving T = 2 π √(I/(Mgd)).
A simple pendulum is an idealization: all the mass sits at one point, a distance L from the pivot, so T = 2 π √(L/g). A real swinging object — a meter stick, a swinging door, a disk on a nail — has mass spread out along its whole length, and every bit of that mass resists angular acceleration differently depending on how far it sits from the pivot. That resistance is the moment of inertia I, and it replaces the simple pendulum's L in the physics.
Gravity pulls down on the center of mass, a distance d from the pivot. When the body is displaced by angle theta, that weight creates a restoring torque tau = -Mgd sin(theta), which for small angles becomes -Mgd theta. Newton's second law for rotation, tau = I alpha, then gives I (d2 theta/dt2) = -Mgd theta, the same differential equation as simple harmonic motion but with I/Mgd playing the role of L/g. Solving gives angular frequency omega = √(Mgd/I) and period T = 2 π √(I/(Mgd)). Everything about the swing — how fast, how the amplitude decays if there's friction, how it responds to a driving force near resonance — flows from this same equation; only I and d change from object to object.
This is the same restoring-torque idea as a torsion pendulum or a swinging spring system: find what provides the restoring torque or force, write Newton's second law, and match it to the SHM equation. The physical pendulum is the bridge between point-mass oscillators and rotational dynamics, and it shows that period is never just about size — it's about how mass is distributed relative to the pivot.
Key terms
- physical pendulum
- Any rigid, extended body that oscillates about a pivot under gravity, as opposed to an idealized point mass on a string.
- moment of inertia (I)
- A measure of how a body's mass is distributed relative to an axis, determining its resistance to angular acceleration.
- restoring torque
- The torque from gravity acting at the center of mass that pulls the pendulum back toward equilibrium.
- parallel axis theorem
- A rule for finding I about any axis: I = I_cm + Md2, where d is the distance from the center of mass to that axis.
- center of mass distance (d)
- The distance from the pivot to the body's center of mass, which sets the strength of the restoring torque.
Watch it explained
- How it worksHow does gravity acting at the center of mass supply the restoring torque on a rigid pendulum?
- Worked exampleFind the period of a uniform 1.0 m rod swinging as a pendulum about one end.
- Worked exampleFind the period of a 0.4 kg disk of radius 0.2 m pivoted at a point on its rim.
- Common mistakeWhy doesn't a physical pendulum's period use the full distance out to its far end?
Check yourself
End of topic.