AP® Precalculus · Unit 4 · Topic 4.9
Vector-Valued Functions
A vector-valued function gives a particle's position as an arrow (x(t), y(t)) at each time t. Its derivative gives the velocity vector, which points in the direction of motion and whose magnitude is the speed.
Two separate equations, x(t) and y(t), tell you where a particle is, but they don't show it moving. Bundle them into one position vector r(t) = (x(t), y(t)) and now you have a single arrow from the origin to the particle, growing and swinging as t changes. That arrow is the whole path in one object: trace its tip and you get the curve; watch it tick forward in t and you get the motion.
Take the derivative of each coordinate separately: r'(t) = (x'(t), y'(t)). This is the velocity vector. At any instant, it points in the exact direction the particle is heading, because it's built from the instantaneous rates of change of x and y, the same way a tangent line shows the direction of a curve at a point. The position vector's length just tells you how far the particle is from the origin, which has nothing to do with how fast it's moving or which way. Speed only shows up when you take the magnitude of the velocity vector: speed = √((x'(t))2 + (y'(t))2). That formula is really the distance formula applied to a rate instead of a displacement.
This topic is where parametric equations, which you already differentiate piece by piece, meet vectors as objects you can add and scale. It also sets up matrices later in the unit: a position vector can be multiplied by a matrix to rotate, stretch, or reflect the whole path, turning one moving point into a tool for describing much more complicated motion.
Key terms
- Position vector
- The arrow r(t) = (x(t), y(t)) from the origin to the particle's location at time t.
- Velocity vector
- The derivative r'(t) = (x'(t), y'(t)), pointing in the particle's direction of motion.
- Magnitude
- The length of a vector, found with the Pythagorean formula √(a2 + b2) for vector (a, b).
- Speed
- The magnitude of the velocity vector, equal to √((x'(t))2 + (y'(t))2).
Watch it explained
- How it worksHow does the velocity vector at a moment point along the direction of travel?
- Worked exampleFind the position and the velocity vectors at t = 2 for the path x(t) = t² and y(t) = 4t - t².
- Common mistakeWhy doesn't the magnitude of the position vector tell you how fast the particle is going?
- Ties togetherHow does the magnitude of the velocity vector turn into the speed of the particle?
Check yourself
End of topic.