ACT® · Math: Number and Quantity
Operations with Complex Numbers
Multiplying complex numbers means FOIL plus one swap: replace i2 with -1 so the four terms collapse into a + bi. Dividing means multiplying by the conjugate so the denominator becomes a real number.
Adding complex numbers is easy because you just combine like parts: real with real, imaginary with imaginary, nothing crosses over. Multiplying is different because every term in the first number has to touch every term in the second. That means four products instead of two, the same FOIL pattern you'd use on any two binomials. The twist is the last term, which comes out as i times i. Since i2 = -1, that term flips from imaginary to real. So a process that starts with four separate terms ends up with only two: a real part and an imaginary part, because one of the four pieces secretly belonged with the real numbers all along.
Division has no direct move the way multiplication does, so it borrows a trick: multiply top and bottom by the conjugate of the denominator. The conjugate just flips the sign of the imaginary part, and when you multiply a complex number by its own conjugate, the cross terms cancel and the i2 term turns positive, leaving (real part)2 + (imaginary part)2, a plain real number. That clears i out of the denominator completely, so you're left dividing a complex numerator by an ordinary real number, which splits cleanly into a + bi form.
Both operations lean on the same fact, i2 = -1, just used in different directions: multiplication uses it to simplify, division uses it to rationalize. This sits right next to the rest of the number-system questions on the test, where you're expected to treat i like a variable that obeys one extra rule, then clean up at the end.
Key terms
- Imaginary unit (i)
- The number defined by i2 = -1, used to build complex numbers.
- Complex number
- A number written as a + bi, with a and b real and i the imaginary unit.
- Conjugate
- The complex number formed by flipping the sign of the imaginary part, turning a + bi into a - bi.
- FOIL
- The method of multiplying two binomials by pairing First, Outer, Inner, Last terms.
- Rationalizing the denominator
- Multiplying top and bottom by the conjugate to remove i from the denominator.
Watch it explained
- How it worksHow does swapping i squared for -1 collapse four terms back into a + bi form?
- Worked exampleFind the product of (3 + 2i) and (4 - 5i) and write it in a + bi form.
- How it worksHow does multiplying by the conjugate sweep i out of a denominator completely?
- Worked exampleWalk me through dividing (2 + 3i) by (1 - i) using the conjugate.
- Common mistakeWhy isn't there still an i left in the answer when (3 + 2i) multiplies (3 - 2i)?
Check yourself
End of topic.