JentooACT®

ACT® · Math: Number and Quantity

Powers of i

Powers of i repeat in a cycle of four: i, -1, -i, 1, then back to i. To find any power of i, divide the exponent by 4 and use the remainder.

i is defined by i2 = -1. Every higher power is built from that one fact. i1 = i, i2 = -1, i3 = i2 times i = -i, and i4 = i2 times i2 = (-1)(-1) = 1. Once you hit i4 = 1, the pattern resets: i5 is just i4 times i, which is 1 times i = i again. So the four values i, -1, -i, 1 repeat forever in that order, because multiplying by i4 never changes anything.

That makes exponents on i a question of leftovers, not full multiplication. Any exponent n splits into whole groups of 4 plus a remainder: n = 4q + r, where r is 0, 1, 2, or 3. Each group of 4 contributes a factor of i4 = 1, so it vanishes, and the whole power of i equals ir. Finding i57 means finding 57 divided by 4, which is 14 remainder 1, so i57 = i1 = i. No repeated multiplication needed.

This idea connects to the rest of complex number arithmetic on the test: once you can reduce any power of i to one of four values, you can simplify expressions, multiply complex numbers, and handle problems mixing real and imaginary parts without getting bogged down. It is a small mechanical skill, but it shows up anywhere an exponent on i appears, so spotting the remainder fast is the whole game.

Key terms

i
The imaginary unit, defined so that i2 = -1.
cycle of four
The repeating pattern i, -1, -i, 1 that powers of i follow forever.
remainder
What's left after dividing the exponent by 4; it determines which of the four values a power of i equals.
i4 = 1
The key fact that makes every full group of four in an exponent disappear from the final value.

Watch it explained

  1. How it worksHow does dividing an exponent by 4 tell you which of i, -1, -i or 1 you land on?
  2. Worked exampleFind the value of i57 without multiplying i by itself 57 times.
  3. Common mistakeWhy isn't i raised to any large even power always equal to 1?

Check yourself

Your turneasy1 of 3
Find the value of 7 times i4k + 2, where k = 9.

End of topic.