JentooPhysics 1

AP® Physics 1: Algebra-Based · Unit 1 · Topic 1.3

Velocity-Time Graphs: Slope and Area

On a velocity-time graph, the slope at any point is the acceleration, and the area between the line and the time axis is the displacement over that interval.

Velocity tells you how fast position is changing, so to get back to position you need to undo that rate — and that's exactly what area does. Picture the velocity graph chopped into thin vertical strips. Each strip has width dt (a tiny slice of time) and height v (the velocity during that slice). Multiply them and you get v times dt, a tiny displacement — distance equals rate times time, just applied to a sliver. Stack up all those thin rectangles across the whole interval and you've rebuilt the total displacement. That's why area under a velocity-time graph is displacement, no matter what shape the graph makes.

Slope works the other way. Slope is rise over run, and on a velocity-time graph the rise is change in velocity and the run is change in time — which is the definition of acceleration. A steep line means velocity is changing fast, so acceleration is large; a flat line means constant velocity and zero acceleration; a straight diagonal line means constant acceleration, since the slope never changes.

This graph is the middle sibling of the three motion graphs. Its slope gives you the acceleration-time graph, and its area gives you the position-time graph — same logic that linked position and velocity graphs before it, now one level up. Watch the sign of the area closely, because that sign is what separates total distance from net displacement.

Key terms

Displacement
The signed straight-line change in position, equal to the net area under a velocity-time graph.
Distance traveled
The total length of the path covered, ignoring direction, found by adding all areas as positive.
Slope
Rise over run on a graph; on a velocity-time graph it equals acceleration.
Area under the curve
The region between the graphed line and the time axis, representing displacement on a velocity-time graph.

Watch it explained

  1. How it worksWalk me through building up displacement out of thin rectangles under a velocity graph.
  2. How it worksHow does the steepness of a velocity-time graph hand you the acceleration?
  3. Worked exampleFind the displacement from a velocity graph rising in a straight line from 0 to 12 m/s over 6 s.
  4. Going furtherWhat does area that sits under the time axis on a velocity graph do to the total displacement?

Check yourself

Your turn1 of 2
A velocity-time graph rises in a straight line from 0 to 19 m/s over 9 s. Find the displacement, in meters, given by the area under the graph.

End of topic.