JentooSAT®

SAT® · Math: Algebra

Given One Quantity, Finding the Other

When an equation has two unknowns but you're told the value of one, substitution turns it into a one-variable equation you solve directly. One equation can only pin down one unknown at a time.

A linear equation like Ax + By = C has two unknowns, so by itself it describes a whole line of possible pairs (x, y). It can't tell you one specific answer. But the moment you're told what one of the variables equals, that freedom disappears. Plug the known value in, multiply it out, and the equation collapses into a single-variable equation: one unknown, one equation, one answer. That's the whole engine behind this question type, whether the letters stand for x and y or for real things like adult and child tickets.

The mechanism never changes: substitute the given number for its variable, simplify the constant term, then isolate the remaining variable with normal equation-solving moves. In a word problem, read the setup first so you know what each variable counts before you substitute, since the arithmetic is identical but the meaning of the leftover variable is the whole point of the question.

This sits right next to solving systems of equations, where you have two equations and need both to pin down both variables. Here you're handed one of those two pieces of information directly, so only one equation is doing any work. It also connects to reading real-world constraints: not every algebraic solution matches the situation, which is why checking whether an answer makes sense in context matters as much as the algebra that produced it.

Key terms

Substitution
Replacing a variable with a known numeric value before solving the rest of the equation.
Linear equation in two variables
An equation of the form Ax + By = C whose solutions are pairs of values, not a single number.
Isolate
To rearrange an equation so the unknown variable stands alone on one side.
Context constraint
A real-world limit, like a total budget or a ticket count, that rules out some mathematically valid solutions.

Watch it explained

  1. How it worksHow do you substitute a known value into Ax + By = C and solve the one variable left standing?
  2. Worked exampleFind y when 6x + 5y = 95 and x equals 10.
  3. Worked exampleFind how many child tickets sell when 14a + 9c = 1080 and 45 adult tickets were sold.
  4. Common mistakeWhy doesn't a value of x that forces y to come out negative always count as a real possibility?

Check yourself

Your turneasy1 of 3
Find y when 7x + 6y = 155 and x = 5.

End of topic.