AP® Physics C: Mechanics · Unit 1 · Topic 1.3
The Constant-Acceleration Equations
The constant-acceleration equations are shortcuts built by integrating a fixed acceleration once to get velocity and again to get position. They only work when acceleration truly never changes.
Position, velocity, and acceleration are linked by derivatives: v is the derivative of x, a is the derivative of v. Run that backward with integrals and, if a is constant, you get three clean formulas: v = v0 + at, x = x0 + v0t + (1/2)at2, and v2 = v02 + 2a(x - x0). They feel like separate rules, but they are all one fact (constant a) unpacked three different ways, each handy for a different missing variable.
The second one comes straight from integration. Integrate a (a constant) once with respect to time: v(t) = v0 + at. Integrate again: x(t) = x0 + v0t + (1/2)at2. The extra constants of integration are just the initial velocity and initial position, pinned down by the conditions at t = 0. The third equation, v2 = v02 + 2a(x - x0), comes from combining the first two and eliminating t algebraically — useful exactly when you don't know or don't care about the time.
These equations are a special case living inside the general derivative and integral relationships from earlier in the unit. The moment acceleration starts changing with time, the integrals a·t and (1/2)at2 are wrong, because they assumed a was a number, not a function. That's the bridge to the next idea: when a(t) actually varies, you must go back to integrating a(t) directly, which is where calculus-based kinematics really earns its keep over the algebra-only version.
Key terms
- Constant acceleration
- Acceleration that has the same value at every instant during the motion being analyzed.
- Constant of integration
- The unknown added when reversing a derivative, fixed here by the initial position or velocity.
- Kinematic equations
- The three algebraic shortcuts relating x, v, a, and t that hold only when a is constant.
- Initial conditions
- The values of position and velocity at time zero, needed to pin down the motion completely.
Watch it explained
- How it worksHow does integrating a constant acceleration twice produce x = x0 + v0t + at2/2?
- Worked exampleFind how far a car traveling 30 m/s goes while braking to a stop at 6 m/s2.
- Worked exampleFind the impact speed of a rock dropped from 45 m using v2 = v02 + 2a times the drop.
- Common mistakeWhy doesn't the kinematic equation with no time in it work for a car whose braking eases off?
Check yourself
End of topic.